There exists a similar question that would lead to the relationship of the given circumference to the unknown value. The radius of the larger circle is 12 cm. The formula for determining the circumference is,
C = 2πr
Substituting the known value,
C = 2π x 12 cm = 24π cm
Thus, the answer is letter B.
Answer:
8 and 12
Step-by-step explanation:
The perimeter of the given rectangle is ...
P = 2(L +W)
P = 2(14 +21) = 2(35) = 70
The scale factor to the similar triangle is ...
similar perimeter/original perimeter = 40/70 = 4/7
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The dimensions of the similar triangle are the original triangle dimensions multiplied by this scale factor:
(14)(4/7) = 8
(21)(4/7) = 12
The sides of the similar triangle are 8 and 12.
Answer:
Yes, as long as it is terminating, or ending and does not repeat forever.
Answer:
Total Surface Area: A = 88 square cm
Step-by-step explanation:
Volume V = 48 cubic cm
So this cuboidal box is actually a rectangular prism.
V = L * W* H
L = length, W = breadth, H= height
With L: W : H = 3: 2: 1
L:W = 3: 2
W: H = 2: 1
L/W = 3/2, L = (3/2)*W
W/H = 2/1 , W = 2*H
L = (3/2)*(2H) = 3H
So : V = L * W * H = (3H) * (2H) * H = 6 * H^3
48 = 6 * H^3
48/6 = 8 = H^3
H = cube-root(8) = 2 cm
so ...
W = 2*H = 2*2 = 4 cm
L = (3/2)*W = (3/2)* 4 = 6 cm
Total Surface Area: A = 2*LW + 2*LH + 2*WH
A = 2*(6 * 4) + 2*(6 * 2) + 2*(4 * 2)
A = 2*24 + 2*12 + 2*8
A = 48 + 24 + 16
A = 48 + 40
A = 88 square cm
Wouldn't it be 45? it's the minimum afterall
