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gulaghasi [49]
4 years ago
12

While a car travels around a circular track at a constant speed, its Acceleration is zero. Velocity is zero. Inertia is zero.

Physics
1 answer:
alexgriva [62]4 years ago
4 0

Answer: None of the options

Explanation:

When we talk about uniform circular motion (constant speed) we yet have a changing velocity and therefore, acceleration.

How is this possible?

Well, velocity is a vector, and as a vector it has magnitude (the speed) and direction. So, while an object performs a uniform circular motion, althought its speed is not changing, its direction does change.

And, since acceleration a is the variation of velocity V in time  t, certainly there is acceleration here.

a=\frac{\Delta V}{\Delta t}

On the other hand, Inertia I is mathematically expressed as:

I=mr^{2}

This means that for a system with a given axis of rotation and a given total mass m, the greater the distance from the axis r to the object that performs the circular motion, the greater the inertia.

This also means that inertia depends directly on the mass of the system and the radius of the circular motion, therefore, as long as these elements exist, in a circular motion the inertia will always be different from zero.

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HURRY!!!!
VMariaS [17]

Answer:

Ted is correct

Explanation:

The equation for gravitational potential energy is PE = m·g·h

The equation for gravitational kinetic energy is KE = 1/2·m·v²

Where:

m = Mass of the object (The racing car)

g = Acceleration due to gravity

h = The height to which the object is raised

v = Velocity of motion of the object

From the principle of conservation of energy, energy can neither be created nor destroyed but changes from one form to another, we have;

Potential energy gained from location at height h = Kinetic energy gained as the object moves down the level ground

m·g·h = 1/2·m·v² canceling like terms gives

g·h = 1/2·v²

v = (√2·g·h)

If the speed is doubled, we have

2·v = 2× (√2·g·h) =  (√2·g·4·h)

Therefore, if 2·v = v₂ then v₂ =  (√2·g·4·h)

Since g, the acceleration due to gravity, is constant, it means that the initial  height must be multiplied or increased 4 times to get the new height, that is we have;

v₂ =  (√2·g·4·h) = (√2·g·h₂)

Where:

4·h = h₂

Which gives;

v₂² = 2·g·h₂

1/2·v₂² = g·h₂

1/2·m·v₂² = m·g·h₂ Just like in the first relation

Therefore, Ted is correct s they need to go up four times the initial height to double the speed.

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