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Sholpan [36]
3 years ago
7

The strength of a gravitational force between two objects depends on

Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:

C. mass and distance.

Explanation:

The strength of a gravitational force between two objects depends on mass and distance.

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A. What are the three longest wavelengths for standing waves on a 240-cm-long string that is fixed at both ends?
vovangra [49]

Answer:

a) the three longest wavelengths = 4.8m, 2.4m, 1.6m

b) what is the frequency of the third-longest wavelength = 75Hz

Explanation:

The steps and appropriate formula and substitution is as shown in the attached file.

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3 years ago
In a bicycle dynamo,does 1. The permanent magnet surrounds a conducting coil 2. The conducting coil rotates when the rear wheel
atroni [7]

Explanation:

3: the electricity is generated in the permanent magnet

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An object moving with a speed of 48 m/s has a kinetic energy of 4,632 J, what is the mass, in kg,
pickupchik [31]

Answer:

4.0 Kg

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

Kinetic energy can be defined as the energy possess by a moving object. Mathematically, it is expressed as:

KE = ½mv²

Where

KE => kinetic energy

m => mass of object

v => velocity

With the above formula, we can obtain the mass of the object as follow:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

KE = ½mv²

4632 = ½ × m × 48²

4632 = ½ × m × 2304

4632 = m × 1152

Divide both side by 1152

m = 4632 / 1152

m = 4.0 Kg

Therefore, the mass of the object is 4.0 Kg

7 0
4 years ago
A ball is thrown straight up from a bridge at a speed of 11.0 m/s. If it takes 5.5 seconds to hit the water below, what is the v
seropon [69]

Answer:

 v = 42.92 m/s

Explanation:

Given,

initial speed of the ball, v = 11 m/s

time taken to hit the ground = 5.5 m/s

velocity of the ball just before it hit the ground, v = ?

time taken by the ball to reach the maximum height

using equation of motion

 v = u + at

final velocity = 0 m/s  

 0 = 11 - 9.8 t

  t = 1.12 s.

time taken by the ball to reach the water from the maximum height

 t' - 5.5 -1.12 = 4.38 s

using equation of motion for the calculation of speed just before it hit the water.

 v  = u + a t

 v = 0 + 9.8 x 4.38

 v = 42.92 m/s

Velocity of the ball just before it reaches the water is equal to v = 42.92 m/s

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4 years ago
two car moving in the same direction have speed of 100km/h-1 and 130km/h.what is the resultant of velocity .shoe carnival in the
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