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Sholpan [36]
3 years ago
7

The strength of a gravitational force between two objects depends on

Physics
1 answer:
9966 [12]3 years ago
7 0

Answer:

C. mass and distance.

Explanation:

The strength of a gravitational force between two objects depends on mass and distance.

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A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts
Juli2301 [7.4K]

Answer:

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

        Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

7 0
3 years ago
The question is on he attachment
atroni [7]

Answer:

A. put water in a container under the pot water will disappear from the container .

3 0
3 years ago
An object weighs 2.6 N in air and 2.2N when completely immersed in water. Determine the relative density of the object (2mks​
frez [133]

Answer:

4.8n

Explanation:

you add 2.6n+2.2n

7 0
3 years ago
(c) The ball leaves the tennis player's racket at a speed of 50 m/s and travels a
Mazyrski [523]

Answer:

t=0.417s

Explanation:

After the ball hits the racket it is in freefall(assume air resistance as negligible)

so a=-g

use

x-x0=v0t+1/2at^2

Plug in givens

20=50t-4.9t^2

Solve quadratic equation using quadratic formula

t= 0.417 seconds, (the other answer is extraneous because it is too big because in 1 second, the ball travels 50 meters)

6 0
3 years ago
a 1kg ball is bening pushed by the rod to move in horizontal groved smooth slot if it startes from angle teta = zero degree . de
viva [34]

The force the rod exerts on the ball at the given angle is determined as 3.94 N.

<h3>Force exerted on the rod by the ball</h3>

The force exerted is calculated as follows;

F = ma

F = mv²/r

F = mω²r

where;

  • m is mass of the ball
  • ω is angular speed of the ball
  • r is radius of the path

r = 2cosθ

<h3>Angular speed when the ball moves 15 degrees</h3>

ωf² = ωi² + 2αθ

where;

  • θ is angular displacement in radians, 15⁰ = 15 x π/180 rad

ωf² = (1)² + 2(2)(15 x π/180)

ωf² = 2.04

ωf = √2.04

ωf = 1.428 rad/s

F = mω²(2cosθ)

F = (1)(1.428)²(2 x cos15)

F = 3.94 N

Learn more about force here: brainly.com/question/12970081

#SPJ1

6 0
2 years ago
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