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Anna007 [38]
3 years ago
5

Two tiny conducting spheres are identical and carry charges of -18.8 µC and +46.5 µC. They are separated by a distance of 2.47 c

m. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive? N
Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

F=-12896N, attractive.

Explanation:

For calculating this force we use the Coulomb Law:

F=\frac{kq_1q_1}{r^2}

Where k=9\times10^9Nm^2/C^{-2} is the Coulomb's constant, q_1 and q_2 the values of each charge and r the distance between them.

Since the Coulomb's constant as I wrote it is in S.I. we have to write all the magnitudes in that system of units, and substitute:

F=\frac{(9\times10^9Nm^2/C^{-2})(-18.8\times10^{-6}C)(46.5\times10^{-6}C)}{(0.0247m)^2}=-12896N

This force is attractive since both charges are of opposite sign.

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The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference
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The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

<h3>Data obtained from the question</h3>
  • Year 1800 percent = 0.028%
  • Year 2013 percent = 0.040%
  • Mass of air = 500 Kg
  • Difference =?

<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
  • Year 1800 percent = 0.028%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
  • Year 1800 percent = 0.040%
  • Mass of air = 500 Kg
  • Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

<h3>How to determine the difference</h3>
  • Mass of CO₂ in year 1800 = 0.14 Kg
  • Mass of CO₂ in year 2013 = 0.2 Kg
  • Difference =?

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

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#SPJ1

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