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Anna007 [38]
3 years ago
5

Two tiny conducting spheres are identical and carry charges of -18.8 µC and +46.5 µC. They are separated by a distance of 2.47 c

m. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive? N
Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

F=-12896N, attractive.

Explanation:

For calculating this force we use the Coulomb Law:

F=\frac{kq_1q_1}{r^2}

Where k=9\times10^9Nm^2/C^{-2} is the Coulomb's constant, q_1 and q_2 the values of each charge and r the distance between them.

Since the Coulomb's constant as I wrote it is in S.I. we have to write all the magnitudes in that system of units, and substitute:

F=\frac{(9\times10^9Nm^2/C^{-2})(-18.8\times10^{-6}C)(46.5\times10^{-6}C)}{(0.0247m)^2}=-12896N

This force is attractive since both charges are of opposite sign.

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why does chelsea see sparks as she removes her clothes from the clothes dryer? conduction. induction. static discharge. loss of
ollegr [7]

Answer:

It would be static discharge and conduction

Explanation:

The conduction of static energy is pulled throughout the clothes and left over static electricity is what causes the spark.

4 0
3 years ago
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Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

where G is the gravitational constant

M is the Earth's mass

R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3

4 0
4 years ago
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Air is being pumped into a spherical balloon so that its volume increases at a rate of 150 cm3/s. How fast is the radius of the
Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

dv/dt = 150cm³/s

d = 2r = 20cm

r = 10cm

find dr/dt

Given that the volume of a sphere is calculated using

v = 4/3πr³

Consider both sides of a derivative

d/dt(v) = d/dt( 4/3πr³)

dv/dt =  4/3π(3r²)dr/dt = 4πr²dr/dt

Hence,

dr/dt = 1/4πr².dv/dt

dr/dt = 1/4π×(10)²×150

dr/dt = 1/4π×100×150

dr/dt = 0.119cm/s.

To know more about radius visit:

brainly.com/question/15053236

#SPJ4

3 0
1 year ago
A golfer imparts a speed of 29.0 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te
Roman55 [17]

Explanation:

It is given that,

Initial speed of a golfer, u = 29 m/s

If it travels the maximum possible distance before landing. It means that it is projected at an angle of 45 degrees.

(a) We need to find the time spent by the ball in the air. It can be calculated by using second equation of motion.

s=ut+\dfrac{1}{2}at^2

Here,

a = -g

s = 0 (it is displacement and it is equal to 0 as the ball lands on the green).

So,

0=29\sin(45)t-\dfrac{1}{2}\times 9.8t^2\ (\text{Initial vertical component of velocity is taken})\\\\-4.9t^2+29\times \dfrac{1}{\sqrt2}t=0\\\\-4.9t^2+20.5t=0\\\\t=0,4.184\ s

So, it will take 4.184 seconds in the air.

(b) let x is the longest hole in one that the golfer can make if the ball does not roll when it hits the green. It can be given by :

x=vt\cos\theta\\\\x=29\times 4.184\times \cos(45)\\\\x=85.79\ m

Hence, this is the required solution.

8 0
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My Fitness Goals: (List your specific and general goals)
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The benefits are vast and the repercussions of failing to stretch can be dramatic.
Do yourself a favor and always stretch before and after a workout. This will promote a healthy cool down, improve flexibility, and reduce next day aches. Failure to stretch can lead to injures and muscle damage.

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This may seem like an obvious one, but it is one of the most important steps to a healthier you. Reducing your body fat has a lot of benefits such as:

Improved joints and tendons
Lowered risk of diabetes
Reduced risk of heart disease
Reduced inflammation
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Improved appearance and confidence
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Crash dieting or pushing yourself too much in the gym can lead to you achieving an unrealistic target, and you may find yourself gaining all the weight you have lost.

Think of it as a lifestyle, and take it slow and steady.

3 0
4 years ago
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