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Phantasy [73]
3 years ago
7

Suppose the three resistors in the picture represents a 240 W

Physics
2 answers:
saw5 [17]3 years ago
4 0

Suppose the three resistors in the picture represents a 240 W television , a 720 W straightening iron and a 1440 W hair dryer, Will the fuse melt or blow ?

➪ <em>The fuse will not blow but it will melt because a fuse never blows up</em><em>.</em><em>The fuse melts down to break the circuit and stop the extreme flow of current.</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>w</em><em>i</em><em>r</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>a</em><em> </em><em>f</em><em>u</em><em>s</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>m</em><em>a</em><em>d</em><em>e</em><em> </em><em>u</em><em>p</em><em> </em><em>o</em><em>f</em><em> </em><em>s</em><em>o</em><em>l</em><em>d</em><em>e</em><em>r</em><em>,</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em> </em><em>m</em><em>e</em><em>l</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em> </em><em>s</em><em>o</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>w</em><em>h</em><em>e</em><em>n</em><em> </em><em>h</em><em>e</em><em>a</em><em>v</em><em>y</em><em> </em><em>c</em><em>u</em><em>r</em><em>r</em><em>e</em><em>n</em><em>t</em><em> </em><em>f</em><em>l</em><em>o</em><em>w</em><em>s</em><em> </em><em>t</em><em>h</em><em>r</em><em>o</em><em>u</em><em>g</em><em>h</em><em> </em><em>i</em><em>t</em><em>.</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>w</em><em>i</em><em>r</em><em>e</em><em> </em><em>m</em><em>e</em><em>l</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em>r</em><em>e</em><em>a</em><em>k</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>i</em><em>r</em><em>c</em><em>u</em><em>i</em><em>t</em><em> </em><em>p</em><em>r</em><em>e</em><em>v</em><em>e</em><em>n</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>i</em><em>t</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>c</em><em>a</em><em>t</em><em>c</em><em>h</em><em>i</em><em>n</em><em>g</em><em> </em><em>f</em><em>i</em><em>r</em><em>e</em><em>.</em><em> </em>

Airida [17]3 years ago
3 0

A fuse is an electrical safety device which should not blow, which should overheat and melts if current is too high. Its placed in the live wire before the switch. This prevents overheating and catching fire. A fuse have a specific current value for example - 3000 amps. So when choosing a suitable fuse you must use the above minimum value but less than maximum value. For example in a circuit there is 1000W flowing, you should choose more than 1000 amps fuse not less or else, it will melt.

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If you took a white piece of plastic to a depth of 180 m, what color would it appear?.
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Explanation:

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2 years ago
What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms
kirza4 [7]

Answer:

F' = (3/2)F

Explanation:

the formula for the electric field strength is given as follows:

E = F/q

where,

E = Electric Field Strength

F = Force due to the electric field

q = magnitude of charge experiencing the force

Therefore,

F = E q   ---------------- equation (1)

Now, if we half the electric field strength and make the magnitude of charge triple its initial value. Then the force will become:

F' = (E/2)(3 q)

F' = (3/2)(E q)

using equation (1)

<u>F' = (3/2)F</u>

3 0
3 years ago
The 1.0-kg collar slides freely on the fixed circular rod. Calculate the velocity v of the collar as it hits the stop at B if it
soldi70 [24.7K]

Answer:

6.21 m/s

Explanation:

Using work energy equation then

U_{1-2}=T_B- T_A\\58d-mgh=0.5m(v_b^{2}-v_a^{2})

where d is displacement from initial to final position, v is velocity and subscripts a and b are position A and B respectively, m is mass of collar, g is acceleration due to gravity

Substituting 1 Kg for m, 0.4m for h, v_a as 0, 9.81 for g then

58(\sqrt{0.4^{2}+0.3^{2}}-0.1)-(1\times 9.81\times 0.4)=0.5\times 1\times (v_b^{2}-v_a^{2})\\19.276=0.5\times 1v_b^{2}\\v_b=6.209025688 m/s\approx 6.21 m/s

7 0
3 years ago
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