Explanation:
Let 
are the number of turns in primary and secondary coil of the transformer such that,
A resistor R connected to the secondary dissipates a power 
For a transformer, 
...............(1)
The power dissipated through the secondary coil is :
.............(2)
Let 
are the new number of turns in primary and secondary coil of the transformer such that,
New voltage is :
...............(3)
So, new power dissipated is 
So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.
Answer:a substance with low ability or no ability to conduct energy
Explanation:
Answer:
dry ice, air fresheners, polar evaporation, arsenic treatment
Answer:
magnitude of the frictional torque is 0.11 Nm
Explanation:
Moment of inertia I = 0.33 kg⋅m2
Initial angular velocity w° = 0.69 rev/s = 2 x 3.142 x 0.69 = 4.34 rad/s
Final angular velocity w = 0 (since it stops)
Time t = 13 secs
Using w = w° + §t
Where § is angular acceleration
O = 4.34 + 13§
§ = -4.34/13 = -0.33 rad/s2
The negative sign implies it's a negative acceleration.
Frictional torque that brought it to rest must be equal to the original torque.
Torqu = I x §
T = 0.33 x 0.33 = 0.11 Nm
