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Phantasy [73]
2 years ago
7

Suppose the three resistors in the picture represents a 240 W

Physics
2 answers:
saw5 [17]2 years ago
4 0

Suppose the three resistors in the picture represents a 240 W television , a 720 W straightening iron and a 1440 W hair dryer, Will the fuse melt or blow ?

➪ <em>The fuse will not blow but it will melt because a fuse never blows up</em><em>.</em><em>The fuse melts down to break the circuit and stop the extreme flow of current.</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>w</em><em>i</em><em>r</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>a</em><em> </em><em>f</em><em>u</em><em>s</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>m</em><em>a</em><em>d</em><em>e</em><em> </em><em>u</em><em>p</em><em> </em><em>o</em><em>f</em><em> </em><em>s</em><em>o</em><em>l</em><em>d</em><em>e</em><em>r</em><em>,</em><em> </em><em>i</em><em>t</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em> </em><em>h</em><em>i</em><em>g</em><em>h</em><em> </em><em>m</em><em>e</em><em>l</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em> </em><em>s</em><em>o</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>w</em><em>h</em><em>e</em><em>n</em><em> </em><em>h</em><em>e</em><em>a</em><em>v</em><em>y</em><em> </em><em>c</em><em>u</em><em>r</em><em>r</em><em>e</em><em>n</em><em>t</em><em> </em><em>f</em><em>l</em><em>o</em><em>w</em><em>s</em><em> </em><em>t</em><em>h</em><em>r</em><em>o</em><em>u</em><em>g</em><em>h</em><em> </em><em>i</em><em>t</em><em>.</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>w</em><em>i</em><em>r</em><em>e</em><em> </em><em>m</em><em>e</em><em>l</em><em>t</em><em>s</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em>r</em><em>e</em><em>a</em><em>k</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>i</em><em>r</em><em>c</em><em>u</em><em>i</em><em>t</em><em> </em><em>p</em><em>r</em><em>e</em><em>v</em><em>e</em><em>n</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>i</em><em>t</em><em> </em><em>f</em><em>r</em><em>o</em><em>m</em><em> </em><em>c</em><em>a</em><em>t</em><em>c</em><em>h</em><em>i</em><em>n</em><em>g</em><em> </em><em>f</em><em>i</em><em>r</em><em>e</em><em>.</em><em> </em>

Airida [17]2 years ago
3 0

A fuse is an electrical safety device which should not blow, which should overheat and melts if current is too high. Its placed in the live wire before the switch. This prevents overheating and catching fire. A fuse have a specific current value for example - 3000 amps. So when choosing a suitable fuse you must use the above minimum value but less than maximum value. For example in a circuit there is 1000W flowing, you should choose more than 1000 amps fuse not less or else, it will melt.

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Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th
Sergio039 [100]

Answer:

The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell q_{inn}=3.50\times10^{-8}\ C

Charge on outer shell q_{out}=1.60\times10^{-8}\ C

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Where, q = charge

k = constant

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}

E=2.38\times10^{4}\ N/C

The total charge enclosed  by a radial distance 20.5 cm

The total charge is

q=q_{inn}+q_{out}

Put the value into the formula

q=3.50\times10^{-8}+1.60\times10^{-8}

q=5.1\times10^{-8}\ C

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}

E=1.09\times10^{4}\ N/C

Hence, The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

7 0
3 years ago
Describa con sus palabras que fue lo que descubrio galileo en su legendario experimento en la torre inclinada de pisa
german

Answer:

En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.  

Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.

 

5 0
3 years ago
Determine the angular velocity of the merry-go-round if a jumps off horizontally in the −n direction with a speed of 2 m/s , mea
lapo4ka [179]

by angular momentum conservation we will have

angular momentum of child + angular momentum of merry go round = 0

angular momentum of child = mvR

m = mass of child

R = radius of child

v = speed = 2 m/s

now let's say moment of inertia of merry go round is I

so we will have

m*2*R + Iw = 0

w = -\frac{2mR}{I}

so merry go round will turn in opposite direction with above speed

6 0
3 years ago
A wire is carrying current vertically downward. What is the direction of the force due to Earth's magnetic field on the wire?
andrey2020 [161]

Answer: The correct option is A ( horizontally towards the east)

Explanation:

Magnetic field is a region around a magnet or a current- carrying conductor, where a magnetic force is experienced. The magnetic effect of electric current was first discovered in the early 1820 by Oersted. Using a wire that had current flowing through it and a pivoted magnetic needle, he discovered that the direction of deflection depended on the direction of the current and whether the wire was above or below the needle.

From the way the needle turns when current when current carrying wire is held parallel to it, he therefore concluded that:

--> a current has magnetic field all round it,

--> the magnetic field is in a direction perpendicular to the current.

The above discovery was now modified in Fleming's left hand rule which states that when conductor carrying current is placed in a magnetic field, the conductor will experience a force perpendicular to both the field and the flow of current.

Therefore from the question, a vertical wire carrying current in DOWNWARD direction is placed in a HORIZONTAL magnetic field directed to the NORTH. The direction of the force on the wire is to the EAST.

4 0
3 years ago
A bicycle wheel with radius 0.3 m rotates from rest to 3 rev/s in 5 s. What is the magnitude and direction of the total accelera
AlekseyPX

Answer:

Explanation:

Given

Radius of bicycle wheel r=0.3\ m

Initial angular velocity \omega _0=0

It rotates 3 revolution in 5 s therefore

\omega =2\pi 3=\6\pi =18.85\ rad/s

using \omega =\omega _0+\alpha t

where \alpha =angular\ acceleration

\omega =Final\ angular\ velocity

t=time

\alpha =\frac{18.85}{5}=3.77 rad/s^2

Total acceleration of any point will be a vector sum of tangential acceleration and centripetal acceleration

\omega at t=1

\omega =0+3.77\times 1=3.77 rad/s

a_c=\omega ^2\cdot r

a_c=(3.77)^2\cdot 0.3=4.26 m/s^2

Tangential acceleration a_t=\alpha \times r

a_t=3.77\times 0.3=1.13 m/s^2

a_{net}=\sqrt{a_t^2+a_c^2}

a_{net}=\sqrt{(1.13)^2+(4.26)^2}

a_{net}=4.41 m/s^2

                       

7 0
3 years ago
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