Can anyone explain and get the answer pls?

A 3,162-kg truck moving with a velocity of 12 m/s to the East hits a 510-kg parked car. The impact causes the car to be set in m

Musya8 [376]

Given:

The mass of the truck is m1 = 3162 kg

The speed of the truck is v1i = 12 m/s in East

The mass of the parked car is m2 = 510 kg

The speed of car is v2i = 0 m/s

The speed of car after collision is v2f = 24 m/s in East

To find the speed of the truck after collision.

Explanation:

The final velocity of the truck will be

$\begin{gathered} m1v1i+m2v2i=m1v1f+m2v2f \\ v1f\text{ =}\frac{m1v1i-m2v2f+m2v2i}{m1} \\ =\frac{3162\times12-510\times24+510\times0}{3162} \\ =8.129\text{ m/s} \end{gathered}$

Thus, the speed of the truck after collision is 8.129 m/s

6 0

1 year ago

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajector

Pavlova-9 [17]

Answer:

$v=7905m/s$

$t=5063s$

Explanation:

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6370 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth?

The weight of the satellite is the centripetal force, so:

$W=mg=F_{cp}=ma_{cp}=m\frac{v^2}{r}$

Which means: $g=\frac{v^2}{r}$

We can calculate then the velocity:

$v=\sqrt{gr}=\sqrt{(9.81m/s^2)(6370000m)}=7905m/s$

For calculating how long will it take for the satellite to complete one trip around Earth we consider that the distance of the trip is the circumference of the orbit. This is calculated as $C=2\pi r$ .

Since velocity is v=d/t, we have:

$t=d/v=C/v=2\pi r/v=\frac{2\pi 6370000}{7905m/s} =5063s$

5 0

3 years ago

Block A, with a mass of 4 kg, is moving with a speed of 2 m/s while Block B, with a mass of 8.4 kg, is moving in the opposite di

dybincka [34]

Answer:

The center of mass move with the velocity of -3.487 m/s.

Explanation:

Given values of block A.

Mass of block A, (M1) = 4 kg

Speed of block A, (V1) = 2 m/s

Given values of block B.

Mass of block B, (M2) = 8.4 kg

Speed of block B, (V2) = -6.1 m/s

Below is the formula to find the velocity of center of mass.

$Velocity = \frac{M1V1 + M2V2}{M1 + M2} \\$

$= \frac{4 \times 2 + 8.4 \times (-6.1) }{4 + 8.4} \\$

$= \frac{- 43.24}{12.4}\\$

$= - 3.487 m/s$

7 0

3 years ago

a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$