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Juli2301 [7.4K]

3 years ago

5

A yellow ball with a mass of 2 kg is rolling across the floor at 3 mis. A red ball with a mass of 3 kg is rolling across th

1 answer:

vodka [1.7K]3 years ago

3 0

The equation for kinetic energy is
Ke=1/2mv^2

Therefore, the yellow ball would be 1/2(2)(3)^2 and red would be 1/2(3)(3)^2. The red ball would have a greater kinetic energy

Red ball= 13.5
Yellow ball=9

The answer would be B because the red ball has a greater mass

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Which is a standard unit of measurement

ruslelena [56]

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2 years ago

True or false? Nitrogen in the atmosphere is responsible for clouds and precipitation? If not what is?

Flura [38]

A.)

False
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6 0

3 years ago

As a quality test of ball bearings, you drop bearings (small metal balls), with zero initial velocity, from a height of 1.94 m i

11Alexandr11 [23.1K]

Answer:

The average acceleration of the bearings is $0.77\times10^{3}\ m/s^2$

Explanation:

Given that,

Height = 1.94 m

Bounced height = 1.48 m

Time interval $t=14.86\times10^{-3}\ s$

Velocity of the ball bearing just before hitting the steel plate

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$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$9.8\times1.94=\dfrac{1}{2}\times v^2$

$v=\sqrt{2\times9.8\times1.94}$

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Negative as it is directed downwards

After bounce back,

We need to calculate the velocity

Using conservation of energy

$mgh=\dfrac{1}{2}mv^2'$

Put the value into the formula

$9.8\times1.48=\dfrac{1}{2}\times v^2'$

$v'=\sqrt{2\times9.8\times1.48}$

$v'=5.38\ m/s$

We need to calculate the average acceleration of the bearings while they are in contact with the plate

Using formula of acceleration

$a=\dfrac{v-v'}{t}$

Put the value into the formula

$a=\dfrac{5.38-(-6.166)}{14.86\times10^{-3}}$

$a=776.98\ m/s^2$

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Hence,The average acceleration of the bearings is $0.77\times10^{3}\ m/s^2$

6 0

2 years ago

Two people were pulling this thing with 560 Newton. Now they are using a rope with 50°. How much Newton would they need to pull

Brums [2.3K]

Answer:

10 N

Explanation:

While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

MIGHT BE TOTALLY WRONG

4 0

2 years ago

A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x =

frutty [35]

Answer:

θ = (7π / 3) rad

Explanation:

given,

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equation is given as

x = 5 sin (π t + π/3 )

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x = A sin θ

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at t = 2 s

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Phase of the motion at t =2 s is θ = (7π / 3) rad

7 0

3 years ago