I think it is because the electrons repel each other
The pathway for you to be able is in your room you need
To solve this problem it is necessary to apply the principles of conservation of Energy in order to obtain the final work done.
The electric field in terms of the Force can be expressed as
![E = \frac{F}{q} \rightarrow F=Eq](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BF%7D%7Bq%7D%20%5Crightarrow%20F%3DEq)
Where,
F = Force
E= Electric Field
q = Charge
Puesto que el trabajo realizado es equivalente al cambio en la energía cinetica entonces tenemos que
KE = W
KE = F*d
In the First Case,
![4 = (qE)d\\q = \frac{4}{Ed}\\q = \frac{4}{5*7}\\q = 0.1142C](https://tex.z-dn.net/?f=4%20%3D%20%28qE%29d%5C%5Cq%20%3D%20%5Cfrac%7B4%7D%7BEd%7D%5C%5Cq%20%3D%20%5Cfrac%7B4%7D%7B5%2A7%7D%5C%5Cq%20%3D%200.1142C)
In Second Case,
![KE = q E'd](https://tex.z-dn.net/?f=KE%20%3D%20q%20E%27d)
![KE = (0.1142)(40)(7)](https://tex.z-dn.net/?f=KE%20%3D%20%280.1142%29%2840%29%287%29)
![KE = 31.976J](https://tex.z-dn.net/?f=KE%20%3D%2031.976J)
The total energy change would be subject to,
![\Delta KE = 31.976-4](https://tex.z-dn.net/?f=%5CDelta%20KE%20%3D%2031.976-4)
![\Delta KE = 27.976J](https://tex.z-dn.net/?f=%5CDelta%20KE%20%3D%2027.976J)
Therefore the Kinetic Energy change of the charged object is 27.976J
Italian physicist Alessandro Volta discovered that particular chemical reactions could produce electricity, and in 1800 he constructed the voltaic pile (an early electric battery) that produced a steady electric current, and so he was the first person to create a steady flow of electrical charge.
Answer: ![M = 5.98\times 10^{24} kg](https://tex.z-dn.net/?f=M%20%3D%205.98%5Ctimes%2010%5E%7B24%7D%20kg)
Explanation:
We know that force acting on an object due to Earth's gravity on the surface is given by:
![mg = G\frac{Mm}{r^2}\\ \Rightarrow g = \frac{GM}{r^2}](https://tex.z-dn.net/?f=mg%20%3D%20G%5Cfrac%7BMm%7D%7Br%5E2%7D%5C%5C%20%5CRightarrow%20g%20%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D)
where g is the acceleration due to gravity, r would be radius of Earth, M is the mass of Earth and G is the gravitational constant.
It is given that at pole, g = 9.830 m/s² and r = 6371 km = 6371 × 10³ m
![\Rightarrow M = \frac{g\times r^2}{G}](https://tex.z-dn.net/?f=%5CRightarrow%20M%20%3D%20%5Cfrac%7Bg%5Ctimes%20r%5E2%7D%7BG%7D)
![M = \frac{9.830 m/s^2 \times (6371 \times 10^3 m )^2}{6.67 \times 10^{-11} m^3 kg^{-1} s^{-2}}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B9.830%20m%2Fs%5E2%20%5Ctimes%20%286371%20%5Ctimes%2010%5E3%20m%20%29%5E2%7D%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%20m%5E3%20kg%5E%7B-1%7D%20s%5E%7B-2%7D%7D)
![\Rightarrow M = 5.98\times 10^{24} kg](https://tex.z-dn.net/?f=%5CRightarrow%20M%20%3D%205.98%5Ctimes%2010%5E%7B24%7D%20kg)
Hence, Earth's mass is ![5.98\times 10^{24} kg](https://tex.z-dn.net/?f=%205.98%5Ctimes%2010%5E%7B24%7D%20kg)