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3 years ago

8

Which of the following is a type of physical change?

2 answers:

goblinko [34]3 years ago

8 0

Answer is C. All of the others are internal/molecular changes.

Charra [1.4K]3 years ago

7 0

Answer is C

Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds

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The number of players on a regulation Basketball Team?

mixer [17]

Basketball is played with two<span> teams, with </span>4 players<span> from each team on the court at one time. The maximum number of players on the bench differs by league. In international play, a maximum of </span>7 players<span> are allowed on the bench, resulting in a roster of </span>12 players<span>.

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3 years ago

Read 2 more answers

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The right to make treatment choices

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3 years ago

A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(C) 315.426 rad/sec

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

(C) As the disk starts from rest

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago

Suppose you "dig a hole" 52 feet deep and place a baseball machine in the hole, so that the balls fire out at 96 ft /s and land

jok3333 [9.3K]

Answer:

76.73 ft/s

Explanation:

Let the final velocity is v.

initial velocity, u = 96 ft/s

g = 32 ft/s²

height, h = 52 feet

use third equation of motion

v² = u² - 2 gh

v² = 96 x 96 - 2 x 32 x 52

v = 76.73 ft/s

Thus, the speed of the ball as it reaches the ground is 76.73 ft/s.

3 0

3 years ago

What should you do if you get caught in quicksand

balandron [24]

Answer:

-you have to make yourse;f as light as possible so toss your bag, jacket, and shoes.

-Try to take a few steps backwards.

-Keep your arms up and out of the quicksand.

-Try to reach for a branch or person's hand to pull yourself out.

-Take deep breaths.

-Move slowly and deliberately.

8 0

3 years ago