Answer:
Change in momentum of the stone is 3.673 kg.m/s.
Explanation:
Given:
Mass of the ball on the horizontal the surface, m = 0.10 kg
Velocity of the ball with which it hits the stone, v = 20 m/s
According to the question it rebounds with 70% of the initial kinetic energy.
We have to find the change in momentum i.e Δp
Before that:
We have to calculate the rebound velocity with which the object rebounds.
Lets say that the rebound velocity be "v1" and KE remaining after the object rebounds be "KE1".
⇒
⇒
⇒
⇒ Joules (J).
Rebound velocity "v1".
⇒
⇒
⇒
⇒
⇒ m/s ...as it rebounds.
Change in momentum Δp.
⇒
⇒
⇒
⇒
⇒ Kg.m/s
The magnitude of the change in momentum of the stone is 3.673 kg.m/s.
Answer:
<h3>The mass of an object is the same on Earth, in orbit, or on the surface of the Moon. ... 1N=1kg ⋅m/s2. 1 N = 1 kg · m/s 2 . ... The gravitational force on a mass is its weight. ... </h3>
Explanation:
<h3>ILY:)</h3>
The chemical energy in Jay's body, to kinetic energy in the car
The answer is B. desert. Deserts don't get much rainfall to begin with and most of it evaporates.
The right formula to use for this calculation is the heat capacity formula,
Heat absorbed, Q = MCT, Where
M = Mass of the substance = 71
C = Specific heat capacity for iron = 0.450 J/gc
T = Change in temperature = 29 - 11 = 18
Q = 71 * 0.450 *18 = 575.10
The amount of heat absorbed by the iron skillet is 575 J.