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LUCKY_DIMON [66]
3 years ago
9

Driving home from school one day, you spot a ball rolling out into the street (Figure 5-21). You brake for 1.20 s, slowing your

950-kg car from 16.0 m/s to 9.50 m/s.
a) What was the average force exerted on your car during braking?
b) How far did you travel while braking?

Physics
1 answer:
frosja888 [35]3 years ago
7 0
A ) v = v o + a t  ( the acceleration will be negative )
9.50 = 16.0 + a * 1.2
a * 1.2 = -16.0 + 9.50
a * 1.2 = - 6.5 
a = - 6.5 : 1.2
a = - 5.4167 m/s²
F = m * a = 950 kg * 5.4167 m/s²
F = 5,145.8 N ( the average force exerted on a car during braking )
b ) d = v o - a t² / 2
d = 16.0 * 1.2 - ( 5.4167 * 1.2² / 2 ) =
= 19.20 - 3.90 = 15.30 m
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Answer:

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Explanation:

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The induced emf through the solenoid is given by :

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L=\dfrac{\epsilon}{(di/dt)}........(1)

The self inductance of the solenoid is given by :

L=\dfrac{N\phi}{I}.........(2)

From equation (1) and (2) we get :

\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}

N is the number of turns in the solenoid

N=\dfrac{\epsilon I}{\phi (dI/dt)}

N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}

N = 229.28 turns

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N = 230 turns

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Answer:

P = 5880  J

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Answer:

On moon time period will become 2.45 times of the time period on earth

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