All categories

2 years ago

What happens to the car if it is traveling in a circular path suddenly encounters ice?

Physics

2 answers:

pychu [463]2 years ago

8 0

the car's friction is reduced to zero

the car's centripetal force drops to zero

the car continues in a straight path from the point at which it encountered the ice

dimulka [17.4K]2 years ago

5 0

When a car is travelling in a circular path then for the circular motion of the the centripetal force is provided by the friction force

This friction force will help to take turn in circular path

Now during the motion of car if friction suddenly disappear due to which there is no centripetal force will act on it

Since there is no centripetal force on the car so now it will not be able to take turn

so here is the possible outcomes

A.) the car's friction is reduced to zero.

B.) the car's centripetal force drops to zero.

C.) the car continues in a straight path from the point at which it encountered the ice.

You might be interested in

The intensity of the Sun's light in the vicinity of the Earth is about 1000W/m^2. Imagine a spacecraft with a mirrored square sa

NeX [460]

Explanation:

Formula to represent thrust is as follows.

F = $\frac{dP}{dt}$

= $\frac{2p}{dt}$

or, p = $\frac{E}{c}$

$\frac{p}{dt} = \frac{W}{c}$

F = $\frac{2IA}{c}$

= $\frac{2 (1000 W/m^{2})(5.5 \times 10^{3} m)^{2}}{3 \times 10^{8} m/s}$

= 201.67 N

Thus, we can conclude that the thrust is 201.67 N.

8 0

3 years ago

A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st

jeka57 [31]

Answer:

The magnitude of change in momentum is (2mv).

Explanation:

The momentum of an object is given by the product of mass and velocity with which it is moving.

Let the mass of ball is m. A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it struck the wall.

Initial speed of the ball is v and final speed, when it rebounds, is (-v). The change in momentum is given by :

p = final momentum - initial momentum

$p=-mv-mv\\\\p=-2mv$

So, the magnitude of change in momentum is (2mv).

3 0

3 years ago

A honey bee flaps its wings 200 times per second. How much time is required for one wingbeat? Give your answer in milliseconds.

kakasveta [241]

A bees wings move so rapidly that studying them, even seeing them, has proved difficult.
The honeybees have a rapid wing beat honeybee flaps its wings 230 times every second.

Therefore, a bee flaps its wings over 200 times in about 1ms

3 0

3 years ago

Read 2 more answers

A young woman walks up 55 steps to the top of a water slide. She slides

navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0

2 years ago

How much force is required to accelerate a 50 kg mass at 2 m/s

marta [7]

Answer:

F = 100 Newtons

Explanation:

F = ma

F = (50 kg)(2 m/s)

F = 100 kg*m/s

3 0

2 years ago