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Lena [83]
1 year ago
10

Two resistors are connected in parallel two equivalent resistance is 3,75 ohm if one resistor has a resistance of 10ohm what is

the resistance of the second resistor
Physics
1 answer:
yawa3891 [41]1 year ago
5 0

Answer:

6 Ω

Explanation:

Two resistors in parallel  = 3.75   ohm when one is 10 ...

r1 * r2 / (r1+r2) = 3.75

10 r2 / ( 10 + r2 )= 3.75

10 r2 = 37.5 + 3.75r2

6.25 r2 = 37.5

r2 = 6Ω

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Answer:

=3.5 m/s

Explanation:

y = x tanθ - 1/2 g x² / (u²cos²θ )

y = 0.25 , x = 0.5, θ = 40°

.25 = .50 tan40 - .5 x 9.8x x²/ u²cos²40

.25 = .42 - 2.0875/u²

u = 3.5 m / s.

4 0
3 years ago
1. What is the bond angle between the hydrogen atoms in an ammonia (NH3) molecule? 2. What is the bond angle between the oxygen
Klio2033 [76]

The answer is 107 degrees. The geometric shape for ammonia is Trigonal Pyramidal, even though its electron geometry is “Tetrahedral”. This is because ammonia has a lone pair of electrons that occupy its space like the other 3 hydrogens in the geometric structure.

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7 0
3 years ago
Read 2 more answers
Solve this system of equations without graphing and show your reasoning <br><br> 5x+y=7<br> 20x+2=y
tatuchka [14]

Answer:

Explanation:

5x + y = 7

20x - y = -2

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        x = (1/5)

5(1/5) + y = 7

1 + y = 7 .

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8 0
2 years ago
Two similar metal spheres, A and B, have charges of +2.0 x10 –6 coulomb and +1.0 x10 –6 coulomb, respectively, as shown in the d
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4 0
2 years ago
a stone is dropped from the top of 50 m high tower simultaneously another stone is thrown upward with a speed of 20 m/s . calcul
Darina [25.2K]
'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.

For the stone dropped from the 50m tower:

H = +50 - (1/2) G T²

For the stone tossed upward from the ground:

H = +20T - (1/2) G T²

When the stones' paths cross, their <em>H</em>eights are equal.

50 - (1/2) G T² = 20T - (1/2) G T²

Wow !  Look at that !  Add (1/2) G T² to each side of that equation,
and all we have left is:

50 = 20T  Isn't that incredible ? ! ?

Divide each side by 20 :

<u>2.5 = T</u>

The stones meet in the air 2.5 seconds after the drop/toss.

I want to see something: 
What is their height, and what is the tossed stone doing, when they meet ?

Their height is  +50 - (1/2) G T² = 19.375 meters

The speed of the tossed stone is  +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it.  The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.
7 0
3 years ago
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