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2 years ago

Which is the larger value 5 * 10^5 or 3* 10^7

Physics

1 answer:

PSYCHO15rus [73]2 years ago

5 0

Explanation:

5x 10^5= 500,000

3x 10^7= 30,000,000

so the second one

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A spaceship travels at approximately 0. 25c with respect to earth. this means 24 hours at the spaceship will be x hours to us on

Blababa [14]

The time passed on earth is mathematically given as

t' = 24.79 hrs

<h3>What is the time passed on earth?</h3>

Generally, the equation for is time mathematically given as

$t' = \gamma t$

Where

$\gamma = Lorentz\ factor \\\\\gamma = 1/ \sqrt {(1 - v^2/c^2)}$

$t' = t/ \sqrt {(1 - v^2/c^2)}$

Therefore

$t' = 24/ \sqrt {(1 - (0.25c/c)^2) }$

$t'= 24/ \sqrt {(1 - 0.25^2)$

t' = 24.79 hrs

In conclusion, the time passed on earth

t' = 24.79 hrs

Read more about the time

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4 0

1 year ago

Example 7.3

marysya [2.9K]

Answer:

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4 0

2 years ago

From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:

den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

$T^2=\frac{4\pi^2}{GM}a^3$

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

$\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3$

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3 years ago

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I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app

Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

initial velocity of the sprinter, u = 18 km/h

final velocity of the sprinter, v = 27 km/h

time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

$initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\$