Where is 50−−√+5√ located on a number line? A. between 7 and 8 B. between 8 and 9 C. between 9 and 10 D. between 10 and 11
1 answer:
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Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q = -
= 0
Sum of angles in a triangle =
<P + <Q + <S =
048° + 0 + <S =
+ <S =
<S = -
=
<S =
Applying the Sine rule,
=
=
=
=
=
⇒ y =
= 12.703
y = 12.70 km
=
=
=
⇒ x =
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.