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Rainbow [258]
4 years ago
13

How do you solve 9÷m-1=-2

Mathematics
1 answer:
seraphim [82]4 years ago
4 0
Hi!

You need to multiply to remove the variable from the denominator.

The answer is m=-9


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Expand and simplify 2(5x+3)−2(x 2 −3) ​ =10x+6−(2(x 2 −3))= =10x+6−(2x 2 −6)= =10x+6−2x 2 +6= =−2x 2 +10x+12 ​
gulaghasi [49]

Answer:

-2x² + 10x - 12

Step-by-step explanation:

Given the expression 2(5x+3)−2(x^2 −3) ​

Expand

2(5x+3)−2(x^2 −3) ​

= 2(5x)+2(3) -2(x²)-2(-3)

=  10x + 6 - 2x²+6

= 10x -2x²+12

Express in standard form

= -2x² + 10x - 12

7 0
3 years ago
What percent of l0.2 gram of 32 mg
9966 [12]

_____________________________________

\huge\red{\mid{\fbox{\tt{ᴀɴsᴡᴇʀ}}\mid}}

<h3>3.264</h3>

<h3>Solution:</h3>

10.2% × 32

0.102 × 32

= 3.264

_____________________________________

\tt\huge\blue{Lee \: Eun \: Hoon \: Seok}

5 0
3 years ago
Solving simultaneous equations with one quadratic, x^2+y^2=16 and y=x+3
Svetlanka [38]
If y=x+3, then in the first equation you have

x^2+(x+3)^2=x^2+(x^2+6x+9)=2x^2+6x+9=16

Rewriting a bit, you get

x^2+3x+\dfrac92=8

x^2+3x+\dfrac94+\dfrac94=8

\left(x+\dfrac32\right)^2=\dfrac{23}4

x=-\dfrac32\pm\dfrac{\sqrt{23}}2

Now, since y=x+3, you also get

y=-\dfrac32\pm\dfrac{\sqrt{23}}2+3=\dfrac32\pm\dfrac{\sqrt{23}}2

So, there are two solutions here:

(x,y)=\left(-\dfrac32+\dfrac{\sqrt{23}}2,\dfrac32+\dfrac{\sqrt{23}}2\right)
(x,y)=\left(-\dfrac32-\dfrac{\sqrt{23}}2,\dfrac32-\dfrac{\sqrt{23}}2\right)
7 0
3 years ago
Image.......................
babunello [35]

Answer:

10.75

Step-by-step explanation:

The cost of an adult ticket is £6 more than that of a child ticket, so will be shown by c+6.

Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:

(c+6)+(c+6)+c+c+c+c=40.50

6c+12=40.50

6c=28.50

c=4.75

so, a childs ticket is 4.75

now to find the cost of an adult ticket you add 6,

4.75 + 6

= 10.75

3 0
3 years ago
Each week, Mr Smith must make copies for his history class. When he uses both the Xerox and the Hewlett packard copiers, the cop
Pachacha [2.7K]

Answer:

The job will take <u><em>75 minutes</em></u> if the Hewlett Packard copier is broken

Step-by-step explanation:

In this question, we are tasked with calculating the amount of time it will the Xerox copier to finish making the copies whilst working alone

First, let the number of copies to make be x

Thus, the rate at which both copiers deliver when working together is x/30 copies per minute

If the Hewlett Packard is working alone, its rate is x/50 copies per minute

Let the time taken for the Xerox copier to complete its work be y minutes. Its working rate is thus x/y copies per minute

When we add the individual working rates, we have the joint working rate.

Hence, mathematically;

x/50 + x/y = x/30

Multiply through by 1/x

1/50 + 1/y = 1/30

1/y = 1/30 - 1/50

1/y = (50-30)/1500

1/y = 20/1500

20y = 1500

y = 1500/20

y = 75 minutes

Thus, the job will take 75 minutes if the Hewlett Packard copier is broken

5 0
3 years ago
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