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AveGali [126]
3 years ago
9

The apparent displacement of an object as it is viewed from two different positions is known as

Physics
1 answer:
rjkz [21]3 years ago
3 0
This phenomenon is known as parallax. The simplest example is this: if you are sitting in the passenger seat, the gas tank needle may appear to read empty. However, if you are the driver, you will see that you are not on empty, but should get some gas.
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Predict what the MASS would be of something exerting a force of 45N on a spring scale. EXPLAIN how you got
a_sh-v [17]
The mutual forces of gravity between the Earth and an object on or near
its surface are (<em>mass of the object</em>) x (<em>acceleration of gravity on Earth</em>). 
These two forces are equal, and we call their strength the "weight" of
the object.  It's the number shown on the scale as long as nobody has
their thumb on the scale.  In this problem, the force is 45N .  (That's
about 10.12 pounds.)

The acceleration of gravity on Earth is about  9.8 meters per second² .

So    45N = (mass in kilograms) x (9.8 meters per second²)

Divide each side by  9.8 :      Mass = 45/9.8 = <u>4.59 kilograms</u>  (rounded)



8 0
3 years ago
If the current density in a wire or radius R is given by J-k+5,0F wire? R, what is the current in the wire?
Deffense [45]

Answer:

I = R^{2}(K+5)

Explanation:

Given :

J = k+5

Now selecting a thin ring in the wire of radius "r" and thickness dr.

Current through the thin ring is

dI = J X 2πrdr

dI = (K+5) x 2πrdr

Now integrating we get

I = \int_{0}^{R} = (K+5).2\pi rdr

I = (K+5) 2π\int_{0}^{R} rdr

I = (K+5) 2π \frac{R^{2}}{2}

I = R^{2}(K+5)

8 0
3 years ago
Part b suppose the magnitude of the gravitational force between two spherical objects is 2000 n when they are 100 km apart. what
kobusy [5.1K]
<span>b) The force with a distance of 150 km is 889 N c) The force with a distance of 50 km is 8000 N This question looks like a mixture of a question and a critique of a previous answer. I'll attempt to address the original question. Since the radius of the spherical objects isn't mentioned anywhere, I will assume that the distance from the center of each spherical object is what's being given. The gravitational force between two masses is given as F = (G M1 M2)/r^2 where F = Force G = gravitational constant M1 = Mass 1 M2 = Mass 2 r = distance between center of masses for the two masses. So with a r value of 100 km, we have a force of 2000 Newtons. If we change the distance to 150 km, that increases the distance by a factor of 1.5 and since the force varies with the inverse square, we get the original force divided by 2.25. And 2000 / 2.25 = 888.88888.... when rounded to 3 digits gives us 889. Looking at what looks like an answer of 890 in the question is explainable as someone rounding incorrectly to 2 significant digits. If the distance is changed to 50 km from the original 100 km, then you have half the distance (50/100 = 0.5) and the squaring will give you a new divisor of 0.25, and 2000 / 0.25 = 8000. So the force increases to 8000 Newtons.</span>
8 0
3 years ago
Read 2 more answers
A heavy hall with a mass of 3.5 kg is observed to accelerate
LenKa [72]

Answer:

<h2>21 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.5 × 6

We have the final answer as

<h3>21 N</h3>

Hope this helps you

6 0
3 years ago
During Cardiovascular Excercise, what do the heart and lungs do?
skad [1K]
They circulate blood and oxygen throughout your body
6 0
3 years ago
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