All categories

3 years ago

The apparent displacement of an object as it is viewed from two different positions is known as

1 answer:

3 0

This phenomenon is known as parallax. The simplest example is this: if you are sitting in the passenger seat, the gas tank needle may appear to read empty. However, if you are the driver, you will see that you are not on empty, but should get some gas.

You might be interested in

"My distance to the center of the earth is about 4000 miles when I am on the surface. If I go to a height of 8000 miles above th

lord [1]

Given,

Distance from the surface to the center of the earth, d=4000 miles

Distance from the center to you at a height of 8000 miles, a= 8000+4000=12000 miles

The gravitational force acting on a person at the surface is equal to his weight.

From Newton's Universal Law of Gravitation, the gravitational force is

$F=\frac{G\times M\times m}{r^2}$

Where G is the gravitational constant, M is the mass of the earth, m is the mass of the object/person, r is the distance between the center of the earth and the object/person

At the surface, this force is equal to the weight of the person, W=mg

i.e.

$F_s=\frac{G\times M\times m}{d^2}=W$

On substituting the of d,

$W=\frac{\text{GMm}}{4000^2}$

At a height of 8000 miles from the surface, the gravitational force is equal to,

$F_a=\frac{GMm}{12000^2}$

On dividing the above two equations,

$\frac{F_a}{W}=\frac{4000^2^{}}{12000^2}=\frac{1}{9}$

Therefore,

$F_a=\frac{1}{9}W$

Therefore at a height of 8000 miles above the surface of the earth, the force of gravity becomes 1/9 time your weight.

5 0

10 months ago

Can someone help me?

Setler [38]

Answer: (1, 30), (2,10), (3,40), (4,20)

Explanation:

4 0

2 years ago

Simple physics question, check the document. Should take about 3-5 minutes.

Ahat [919]

Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N

5 0

3 years ago

Each of the objects below is dropped from the same height. which one would be least affected by air resistance?

ioda

A weight would be least affected since it would fall striaght down if it was say paper it would go down slower because it has more air resistance due to less weight

3 0

3 years ago

ANSWER FAST PLSSSSSS Use this diagram of the wave below to answer any questions that follow

tigry1 [53]

Answer:

1. Letter A indicates the crest.

2. Letter E indicates the wavelength.

3. Letter C indicates the trough.

Explanation:

1. Determination of the the crest.

A crest is simply defined as a point on a wave where the displacement is maximum (i.e highest).

Considering the diagram given above, the point where the displacement is maximum is A. Therefore, A is the crest of the wave.

2. Determination of the wavelength.

The wavelength of a wave is simply defined as the distance between two successive crest or trough.

Obeserving the diagram above, we can see that E gives the distance between two successive crest. Therefore, E is the wavelength of the wave.

3. Determination of the trough.

A trough is simply defined as a point on a wave where the displacement is minimum (i.e lowest). Thus we can say that the trough is the opposite of the crest.

Considering the diagram given above, the point where the displacement is minimum is C. Therefore, C is the trough of the wave.

7 0

2 years ago