The increase in height as a tsunami approaches shore is due to

Physics

2 answers:

ryzh [129]3 years ago

5 0

Answer:

C. The decrease in speed as the wave approaches shore.

Explanation:

The waves break when approaching the shore because the depth decreases. Thus, the wave travels more slowly and increases its height. There comes a time when the part of the wave on the surface travels faster than the one that travels under water, the ridge destabilizes and falls against the ground.

OleMash [197]3 years ago

3 0

Answer:

Explanation:

A tsunami is a series of successive ocean waves usually caused by landslide, earthquake or volcanic eruption. The speed of a tsunami decreases and its height increases as it moves from the deep part of a water body to the shallow part (e.g shore) of the water body. In other words, for a tsunami, the deeper the water, the slower its speed and consequently the higher it grows. Therefore it is safe to say that an increase in the height of a tsunami as it approaches a shore is due to the decrease in speed as the wave approaches the shore.

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Well if the ship was in space their shouldn’t be a loud bang. Because you can’t hear anything in space

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slavikrds [6]

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Rzqust [24]

Wow ! This is not simple. At first, it looks like there's not enough information, because we don't know the mass of the cars. But I"m pretty sure it turns out that we don't need to know it.

At the top of the first hill, the car's potential energy is

PE = (mass) x (gravity) x (height) .

At the bottom, the car's kinetic energy is

   KE = (1/2) (mass) (speed²) .

You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down. So now, here comes the big jump. Put a comment under
my answer if you don't see where I got this equation:

   KE = 0.9 PE

(1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)

Divide each side by (mass):

   (0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)

(There goes the mass. As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)

Divide each side by (0.9):

   (0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)

Divide each side by (9.8 m/s²):

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3 years ago

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kumpel [21]

Answer:

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Explanation:

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