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tatyana61 [14]
3 years ago
9

The increase in height as a tsunami approaches shore is due to

Physics
2 answers:
ryzh [129]3 years ago
5 0

Answer:

C. The decrease in speed as the wave approaches shore.

Explanation:

The waves break when approaching the shore because the depth decreases. Thus, the wave travels more slowly and increases its height. There comes a time when the part of the wave on the surface travels faster than the one that travels under water, the ridge destabilizes and falls against the ground.

OleMash [197]3 years ago
3 0

Answer:

(c) The decrease in speed as the wave approaches the shore.

Explanation:

A tsunami is a series of successive ocean waves usually caused by landslide, earthquake or volcanic eruption. The speed of a tsunami decreases and its height increases as it moves from the deep part of a water body to the shallow part (e.g shore) of the water body. In other words, for a tsunami, the deeper the water, the slower its speed and consequently the higher it grows.  Therefore it is safe to say that an increase in the height of a tsunami as it approaches a shore is due to the decrease in speed as the wave approaches the shore.

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A mass of 3.0 kg rests on a smooth surface inclined 34° above the horizontal. It is kept from sliding down the plane by a spring
azamat

Answer:

The spring stretched by x = 13.7 cm

Explanation:

Given data

Mass = 3 kg

k = 120 \frac{N}{m}

Angle \theta = 34°

From the free body diagram

Force acting on the box = mg sin\theta

⇒ F = 3 × 9.81 × \sin34

⇒ F = 16.45 N ------- (1)

Since box is attached with the spring so a spring force also acts on the box.

F_{sp} = k x

F_{sp} = 120 x -------- (2)

The net force acting on the body is given by

F_{net} = ma

Since acceleration of the box is zero so

F_{net} = 0

F - F_{sp} = 0

F = F_{sp}

Put the values from equation (1) & (2) we get

16.45 = 120x

x = 0.137 m

x = 13.7 cm

Therefore the spring stretched by x = 13.7 cm

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3 years ago
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