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3 years ago

The increase in height as a tsunami approaches shore is due to

Physics

2 answers:

ryzh [129]3 years ago

5 0

Answer:

C. The decrease in speed as the wave approaches shore.

Explanation:

The waves break when approaching the shore because the depth decreases. Thus, the wave travels more slowly and increases its height. There comes a time when the part of the wave on the surface travels faster than the one that travels under water, the ridge destabilizes and falls against the ground.

OleMash [197]3 years ago

3 0

Answer:

Explanation:

A tsunami is a series of successive ocean waves usually caused by landslide, earthquake or volcanic eruption. The speed of a tsunami decreases and its height increases as it moves from the deep part of a water body to the shallow part (e.g shore) of the water body. In other words, for a tsunami, the deeper the water, the slower its speed and consequently the higher it grows. Therefore it is safe to say that an increase in the height of a tsunami as it approaches a shore is due to the decrease in speed as the wave approaches the shore.

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2 years ago

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a golfer is on the edge of a 12.5m bluff overlooking the 18th hole which is located 67.1m from the base of the bluff. she launch

Alja [10]

Answer: $26.359 m/s$

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_{o}cos \theta t$ (1)

$y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}$ (2)

$V=V_{o}-gt$ (3)

Where:

$x=67.1 m$ is the horizontal distance traveled by the golf ball

$V_{o}$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

$t$ is the time

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$g=9.8 m/s^{2}$ is the acceleration due gravity

$V$ is the final velocity of the ball

Let's begin by finding $t$ from (2):

$t=\sqrt{\frac{2 y_{o}}{g}}$ (4)

$t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}$ (5)

$t=1.597 s$ (6)

Substituting (6) in (1):

$67.1 m=V_{o} cos(0\°) 1.597 s$ (7)

Finding $V_{o}$ :

$V_{o}=42.01 m/s$ (8)

Substituting $V_{o}$ in (3):

$V=42.01 m/s-(9.8 m/s^{2})(1.597 s)$ (9)

Finally:

$V=26.359 m/s$

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3 years ago

Can someone PLEASE help me with this. Anyone that’s good in physics pls

kolbaska11 [484]

Answer:

RT = 35 Ohms

Explanation:

Let the three resistors be R1, R2 and R3 respectively.

Given the following data;

R1 = 14 Ohms

R2 = 12 Ohms

R3 = 9 Ohms

To find the total resistance, RT;

Since all the resistors are connected in series, the total resistance is equal to the sum of all three resistance of the resistors.

RT = R1 + R2 + R3

Substituting into the equation, we have

RT = 14 + 12 + 9

RT = 35 Ohms.

Therefore, the total resistance of the circuit is 35 Ohms.

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AveGali [126]

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2 years ago

A 230.0 kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and the b

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Well, it's equal to the weight of the bear, which is 230*10=2300 N

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