In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t,
= 49.6/6 = 8.267 m/s
Answer:
1 × 10⁶ N/C
Explanation:
The magnitude of the electric field between the membrane = surface density / permittivity of free space = 10 ⁻⁵C/ m² / (8.85 × 10⁻¹²N⁻¹m⁻²C²) = 1.13 × 10⁶ N/C approx 1 × 10⁶ N/C
Answer:
x = 0.0873 m
Explanation:
given,
length of clothesline = 10 m
the line sags to create an angle that is 1 degree below the horizontal on each end.
As mass is hang at the center the angle made let the deflection be 'x'
as the shirt is hang at the center distance will be equal to 5 m.
now




x = 0.0873 m
Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.