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Natali [406]
4 years ago
8

You have 4/5 cup of brown sugar in your cupboard. the recipe for a dessert calls for 1/4 cup of brown sugar. how much brown suga

r would you have left if you made the dessert? what is the answer in simplest terms?
Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
7 0

Answer:


Step-by-step explanation:

4/5 cup of brown sugar. Needs 1/4 cup. How many cups left?

Okay, so 4/5 = 0.80, 1/4=0.25.

0.80-0.25=0.55

Which is 55/100

Divide both numbers by 5

11/20

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Point P coordinates (-6,6) and P' is it's reflection across the x axis
Alexeev081 [22]
If you need the coordinates of p' then the answer is (-6,-6)
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3 years ago
Please help!! markup and markdown word problem.
12345 [234]

Step-by-step explanation:

"markup" contains "up". so, the price goes "up". this is actually increasing the price (e.g. by calculating the profit margin of selling an item on top of the cost of buying the item from the manufacturer).

"markdown" contains "down". so, the price goes "down". e.g. with discounts.

here we have a markup. it is 150%.

that means the price goes up by 150% compared to the original cost.

so, the computer game costs in the store

the original cost + 1.5× original costs

25 + 1.5×25 = 2.5×25 = $62.50

3 0
3 years ago
2/5 of the instruments in the marching band are brass, 1/3 are percussion, and the rest ate woodwinds. What fraction of the band
Ilia_Sergeevich [38]
6/15 = brass
5/15= percussion
6/15+5/15= 11/15
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5 0
4 years ago
If 24 = 118, what is the measure of each of the other<br> angles?
vova2212 [387]

Answer:

Step-by-step explanation:

Lines l and m are the parallel lines and line n is a transversal intersecting parallel lines.

Since, m∠2 = m∠4 = 118° [Given]

m∠2 = m∠6 = 118° [Corresponding angles]

m∠4 = m∠8 = 118° [Corresponding angles]

m∠1 + m∠2 = 180° [Linear pair of angles]

m∠1 = 180° - 118° = 62°

m∠1 = m∠5 = 62° [Corresponding angles]

m∠3 = m∠1 = 62° [Corresponding angles]

m∠7 = m∠5 = 62° [Corresponding angles]

4 0
3 years ago
Solve the equation 5x + (−2) = 6x + 4 using the algebra tiles. What tiles need to be added to both sides to remove the smaller x
miss Akunina [59]

Answer:

a) Adding -5x on both sides of the equation to remove the smaller x-coefficient

b) Adding -4 on both sides will remove the constant from the right side of the equation

Step-by-step explanation:

Given equation:

5x + (−2) = 6x + 4

a) What tiles need to be added to both sides to remove the smaller x-coefficient?

Smaller x-coefficient is 5x to remove the smaller x-coefficient

So, Adding -5x on both sides of the equation to remove the smaller x-coefficient

b) What tiles need to be added to both sides to remove the constant from the right side of the equation?

the constant on right side is 4

Adding -4 on both sides will remove the constant from the right side of the equation

6 0
3 years ago
Read 2 more answers
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