1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antoniya [11.8K]
3 years ago
13

Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of

55 km/hour, while car B travels at a constant speed of 12 km/hour. How long will it take care from t=0 for car A to meet car B?
Select one:
a. 24.5 s
b. 490 s
c. 245 s
d. 268 s
e. None of the above.
Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

<em>d. 268 s</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\displaystyle t=\frac{5}{67}

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

You might be interested in
A hockey puck wont slide very far on concrete or asphalt, but it will slide for a very long time on ice. Why is this?
Ilya [14]
When hockey players push the puck along the ice it slides causing heat which melts the ice causing the friction against the ice to be less.
7 0
3 years ago
Read 2 more answers
A ball rolls over the edge of a platform with only a horizontal velocity. The height of the platform is 1.60m and the horizontal
AysviL [449]

Answer:

v = 46.99 m/s

Explanation:

The velocity of the ball just before it touches the ground, is given by the following formula:

v=\sqrt{v_x^2+v_y^2}           (1)

vx: horizontal component of the velocity

vy: vertical component of the velocity

The vertical component vy is calculated by using the following formula:

v_y^2=v_{oy}^2+2gh   (2)

vy: final velocity

voy: initial vertilal velocity = 0m/s  (because it is a semi parabolic motion)

g: gravitational acceleration = 9.8 m/s^2

h: height = 1.60m

You replace the values of the parameters in the equation (2):

v_y=2(9.8m/s^2)(1.60m)=31.36\frac{m}{s}

vx is calculated by using the information about the horizontal range of the ball:

R=v_o\sqrt{\frac{2h}{g}}    (3)

R: horizontal range of the ball = 20.0 m

You solve the previous equation for vo, the initial horizontal velocity:

v_o=R\sqrt{\frac{g}{2h}}=(20.0m)\sqrt{\frac{9.8m/s^2}{2(1.60m)}}\\\\v_o=35\frac{m}{s}

The horizontal component of the velocity is constant in the complete trajectory, hence, you have that

vx = vo = 35 m/s

Finally, you replace the values of vx and vy in the equation (1):

v=\sqrt{(35m/s)^2+(31.36m/s)^2}=46.99\frac{m}{s}

The velocity of the ball just before it touches the ground is 46.99 m/s

5 0
3 years ago
Two bicyclists are accelerating forward in a straight line, and Biker 1 has less mass than Biker 2. If the net force on the bike
Solnce55 [7]

If  Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.​

<h3>What is the Newton second law?</h3>

The Newton second law gives the relationship between the force and the acceleration. We know that; acceleration = Force/mass.

Now if Biker 1 has less mass than Biker 2 it the follows that biker 1 has a greater acceleration than Biker 2.​

Learn more about Newton's law:brainly.com/question/27573481

#SPJ1

4 0
1 year ago
Elements in Group VIIIA (also known as Group 18, or the noble gases) have
Sonbull [250]
The answer is C (the same number of valence electrons)
3 0
3 years ago
Show the weight of the ladder and draw the missing Frictional force.
madreJ [45]
Since there is no friction between the ladder and the wall, there can be no vertical force component. That's the tricky part ;)

So to find the weight, divide the 100N <em>normal</em> force by earths gravitational acceleration, 9.8m/s^2

W =  \frac{N}{g}  =  \frac{100N}{9.8m/s^{2}} =  \frac{100}{9.8} = 10.2kg


Then;
Draw an arrow at the base of the ladder pointing towards the wall with a value of 30N, to show the frictional force.
5 0
3 years ago
Other questions:
  • A student is standing in an elevator that is
    13·1 answer
  • Displacement vector of 4 km north, 2 km south, 5 km north, and 5km south combine to a total displacement of ? A 2 km South b 16
    15·1 answer
  • Divers in Acapulco, Mexico, leap from a point 36m above the sea. What is the velocity when they enter the water? V = distance /
    8·2 answers
  • A light wave encounters a partial physical barrier, such as a wall with a hole in it. What is MOST LIKELY to occur?
    6·2 answers
  • The 49-g arrow is launched so that it hits and embeds in a 1.45 kg block. The block hangs from strings. After the arrow joins th
    5·1 answer
  • Whats potential energy?
    8·2 answers
  • The particles of a GAS within a closed container will collide with the container walls, exerting a FORCE. The force per unit of
    5·2 answers
  • Why does a bowling ball have more<br> gravity than a soccer ball?
    11·2 answers
  • Topic: Chapter 19: Some wiggle room
    8·1 answer
  • 39. What is the change in momentum for a 5,000 kg ship in
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!