1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antoniya [11.8K]
3 years ago
13

Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of

55 km/hour, while car B travels at a constant speed of 12 km/hour. How long will it take care from t=0 for car A to meet car B?
Select one:
a. 24.5 s
b. 490 s
c. 245 s
d. 268 s
e. None of the above.
Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

<em>d. 268 s</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\displaystyle t=\frac{5}{67}

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

You might be interested in
Drag the titles to the correct boxes to complete the pairs.
PilotLPTM [1.2K]
Can you input a picture??
5 0
3 years ago
A car, X, with a mass of 1500 kg is moving west with an acceleration of 0.50 m/s2. A second car, Y, of equal mass is heading eas
ehidna [41]

Answer:

A

Explanation:

8 0
3 years ago
I need help witha worksheet over circuitsin physics could someone help??
garik1379 [7]
Yes u can help I need to see th worksheet to help tho
5 0
3 years ago
(a) what is the system of interest if the acceleration of the child in the wagon is to be calculated? (select all that apply.)
Leno4ka [110]

since child is moving along with the wagon and we need to find the acceleration of child inside that wagon then in this case the system of interest must be child + wagon

System of interest will be the system that is used to find the force or acceleration using Newton's law

Here we have to assume that system on which if we will calculate the forces then the net value of force on that system will help to calculate the unknown quantities

So here our system will be boy + wagon

6 0
3 years ago
(a) what is the acceleration of two falling sky divers (mass 132 kg including parachute) when the upward force of air resistance
Komok [63]

As per the question the mass of two falling sky drivers is 132 kg.

First we have to calculate their acceleration.

Whenever a body falls freely under gravity,its acceleration is acceleration due to gravity i.e g whose value is 9.8 m/s^2.

The earth pulls the object with a force equal to the weight of the body.

Hence the force gravity  F=W= mg   [ here m is mass of the body]

Here m =132 kg.

Hence force of gravity F= mg

                                        =132 kg ×9.8 m/s^2

                                        =1293.6 kg m/s^2

                                         =1293.6 N      [ here N[newton] is the unit of force.]

As per the question the air resistance is one fourth of weight of the bodies.

Hence air resistance F' =1/4 mg

                                       =\frac{1}{4} *1293.6N

                                        =323.4 N

Here F acts in vertically downward direction while F' acts in vertically upward direction.

Hence the net force acting on the particle is F-F'.

                                                 F_{net} =1293.6N -323.4N

                                                         =970.2 N

From Newton's second law of motion we know that net force is the product of mass and acceleration i.e  

                                   F_{net} =ma  [Here a is the acceleration]

                                             a =\frac{F_{net} }{m}

                                                  = \frac{970.2}{132} m/s^2

                                                  =7.35 m/s^2

In the second question it has been told that they descend with uniform speed.hence acceleration of the two bodies will be zero.

 we know that F= ma

                           =m×0

                            =0 N

Hence they will not get any force when they will descend with a uniform speed.


4 0
3 years ago
Other questions:
  • Explain the mathematical equation for KVL (The voltage of a circuit through each component in that circuit is proportional to th
    15·1 answer
  • 8. What are the seven kinds of transverse waves found on the electromagnetic
    8·1 answer
  • What happens to the speed of water waves as it enters a shallow medium .
    10·1 answer
  • If a running system has a total change in heat of 295 joules, and it's running at a temperature of 402 kelvin, what is the entro
    11·1 answer
  • Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
    11·1 answer
  • Mary has a mass of 40 kg and sprints at 1 m/s. How much kinetic energy does she have?
    11·1 answer
  • A hockey puck attached to a horizontal spring oscillates on a frictionless, horizontal surface. The spring has force constant 4.
    5·1 answer
  • What is the time taken for a 80kg mountain climber to climb a 200m mountain ? power output=0.1hp​
    12·1 answer
  • Surveyors frequently use trig functions. Suppose that you measure the angle from your position to the top of a mountain to be 2.
    6·1 answer
  • Modern rechargeable batteries require rare earth elements to build. Why are modern rechargeable batteries expensive and a concer
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!