How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?
1 answer:
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
where q is the charge and
is the potential difference.
In our problem, the work done is W=39 J while the potential difference of the battery is
, so we can find the charge transferred by the battery:
where q is the charge and
In our problem, the work done is W=39 J while the potential difference of the battery is
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Hope it cleared your doubt.
Answer:
The answer is 1.87nm/s.
Explanation:
The water loss must be replaced by
of sap. 110g of sap corresponds to a volume of
thus rate of sap replacement is
The volume of sap in the vessel of length is
,
where is the cross sectional area of the vessel.
For 2000 such vessels, the volume is
taking the derivative of both sides we get:
on the left-hand-side is the velocity
of the sap, and on right-hand-side
; therefore,
and since the cross-sectional area is
;
therefore,
solving for we get:
which is the upward speed of the sap in each vessel.