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sineoko [7]
3 years ago
9

How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?

Physics
1 answer:
sdas [7]3 years ago
3 0
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
W=q \Delta V
where q is the charge and \Delta V is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is \Delta V = 9.0 V, so we can find the charge transferred by the battery:
q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C
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