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3 years ago

How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?

1 answer:

3 0

The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
$W=q \Delta V$
where q is the charge and $\Delta V$ is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is $\Delta V = 9.0 V$ , so we can find the charge transferred by the battery:
$q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C$

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A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

Electric field strength, $E=2.55\times 10^{4}\ N/C$

We know that,

Charge of electron, $q=1.6\times 10^{-19}\ C$

Mass of electron, $m=9.1\times 10^{-31}\ kg$

From the definition of electric field, $F=qE$ ...............(1)

According to Newton's second law, F = ma..........(2)

From equation (1) and (2)

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\ C\times 2.55\times 10^{4}\ N/C }{9.1\times 10^{-31}\ kg}$

$a=0.4483\times 10^{16}\ m/s^2$

$a=4.483\times 10^{15}\ m/s^2$

So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

Hence, it is the required solution.

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3 years ago

A nearsighted eye has a far point of 100 cm. Objects further than 100 cm are not seen clearly. A diverging lens is used to permi

Leya [2.2K]

A diverging lens is used to permit clear vision of an object placed at infinity. The focal length of the lens is -100 cm.

<h3>What is focal length?</h3>

The focal length is half of the radius of curvature of the focal lens.

By the lens maker formula,

1/f = 1/v +1/u

where, v is the image distance and u is the object distance.

Give, the object is at infinity and the image must form at 100 cm, the the focal length will be

1/f = 1/ -100 + 1/∞

f = -100 cm

The focal length must be -100 cm for the diverging lens.

Learn more about focal length.

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6 0

2 years ago

Question 4 (1 point)

NNADVOKAT [17]

Answer: 0.42 Amperes

Explanation:

Given that:

Current, I = ?

Electric charge Q = 100 coulomb

Time, T = 4.0 minutes

(The SI unit of time is seconds. so, convert 4.0 minutes to seconds)

If 1 minute = 60 seconds

4.0 minutes = 4.0 x 60 = 240 seconds

Since electric charge, Q = current x time

i.e Q = I x T

100 coulomb = I x 240 seconds

I = 100 coulomb / 240 seconds

I = 0.4167 Amperes (round to the nearest hundredth which is 0.42 amperes)

Thus, 0.42 Amperes of current flows in the circuit.

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3 years ago

I need help ASAP. This is for 15 points

kramer

Answer:

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measures : the distance east or west of the Prime Meridian

7 0

3 years ago

The speed of light in a vacuum is 299,792,458 m/s. Which gives this number in three significant digits? 299,000,000. m/s 2.99 x

dexar [7]

Answer: $2.99(10)^{-8} m/s$

Explanation:

When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent.

Then, the significant figures (or significant digits) will be the digits that are before the power of ten.

Now, in the case of the number 299,792,458 if we want to write it with three significant digits, we have to write it in scientific notation as:

$2.99(10)^{-8}$

7 0

3 years ago

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