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zhuklara [117]
4 years ago
14

A charge of 4 nc is placed uniformly on a square sheet of nonconducting material of side 17 cm in the yz plane. (a) what is the

surface charge density sigma ?
Physics
1 answer:
Ratling [72]4 years ago
8 0

The charge density of the sheet is 1.384×10⁻⁷C/m².

Charge density is defined as the charge per unit area.

The sheet is a square of length  l=17 cm.

Calculate the area A of the sheet .

A=l^2=(17 cm)^2= (17*10^-^2m)^2=0.0289 m^2

The charge Q on the sheet is

Q=4nC=4*10^-^9C

The charge density σ is given by,

\sigma=\frac{Q}{A}

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>

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A 28 g bullet pierces a sand bag 29 cm thick. If the initial bullet velocity was 55 m/s and it emerged from the sandbag with 18
Bumek [7]

The correct answer to the question is 130.4 N.

CALCULATION;

The mass of the bullet is given as m = 28 gram = 0. 028 kg.

The initial velocity of the bullet u = 55 m/s

The final velocity of the bullet  v = 18 m/s.

The distance covered by the bullet through the sand bag s = 29 cm.

                                                                                                   = 0.29 m

Let the acceleration of the bullet is a .

From equation of kinematics, we know that-

                                         v^2-u^2=\ 2as

                                        ⇒ a=\ \frac{v^2-u^2}{2s}

                                               =\ \frac{(18)^2-(55)^2}{2\times 0.29}\ m/s^2

                                              =\ -4656.897\ m/s^2

The negative sign is used due to the fact that force is opposing in nature. Its velocity is decreasing with time.

From Newton's second law of motion, we know that net force on a body is equal to the product of mass with acceleration.

Mathematically F = ma.

Hence, the frictional force exerted on the bullet is calculated as -

                                              F = m × a

                                                 = 0.028 × (-4656.897) N

                                                 = -130.4 N                     [ANS]

Here, N ( newton) stands for the unit of force.

8 0
3 years ago
Calculate the air pressure in the pressurized tank, if h1 = 0. 18 m, h2 = 0. 2m and h3 = 0. 25m. The density of the mercury, wat
fomenos

The air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

<h3 /><h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

Pressure is found as the product of the density,acceleraton due to gravity and the height.

P₁=ρ₁gh₁

P₁=13,600 kg/m³×9.81 (m/s²)×0.18 m

P₁=24014.88 N/m²

P₂=ρ₂gh₂

P₂= 1000 kg/m³×9.81 (m/s²)×00.2 m

P₂=196.2 N/m²

P₃=ρ₃gh₃

P₃=850 kg/m³×9.81 (m/s²)×0.25

P₃=2084.625  N/m²

Hence,the air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

To learn more about the pressure refer to the link;

brainly.com/question/356585

#SPJ4

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2 years ago
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Answer:

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Explanation:

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v is the final velocity of the astronaut

u is his initial velocity

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s = H = total height covered

The equation will then become;

v² = u²-2gH

Given

u = 60m/s

v = 0m/s

g = ?

H = 72m

Substituting the given value into the equation;

0² = 60²-2g(72)

0 = 3600-144g

-3600 = -144g

g = -3600/-144

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The magnitude of his acceleration due to gravity on the planet is 25m/s²

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Velocity = displacement / time

First, Always make sure that your units for things are the same. In this question, we are given time in seconds and hours. So, we need to make them all use 1 unit.

I will do seconds.

To convert 80km/h to m/s, divide by 3.6.

22.2222…. m/s = displacement / 2.1s

Multiply by 2.1s on both sides

46.6666……m = displacement

You travelled 47 meters.
7 0
2 years ago
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