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Nataly [62]
3 years ago
14

PLEASE HELP WITH THIS(INORDER FOR ME TO GIVE YOU A BRIANLIST,EXPLAIN HOW U GOT IT)(will give brainlist and thanks)(Find the peri

meter)

Mathematics
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer:

7x+10 cm

Step-by-step explanation:

To find the perimeter add up all the sides

There are 5 sides

3x+ 5+ 2x+2x+5

Combine like terms

3x+2x+2x   +5+5

7x + 10

The perimeter is 7x+10 cm

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lions [1.4K]

Answer:

Confidence interval:  (0.04649,0.04913)

Step-by-step explanation:

We are given the following in the question:

Sample size, n =  100,000

Number of people who donated, x = 4781

\hat{p} = \dfrac{x}{n} = \dfrac{4781}{100000} = 0.04781


95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.04781
\pm 1.96(\sqrt{\dfrac{0.04781
(1-0.04781
)}{100000}})\\\\=0.04781
\pm 0.00132\\\\=(0.04649,0.04913)

is the required 95% confidence interval  for the true proportion of their entire mailing list who may donate.

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2 years ago
Factor completely. 3x^2 + 30x + 75 =?​
vladimir1956 [14]

Answer:

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8 0
3 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
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