Answer:
y-4=4(x+1)
Step-by-step explanation:
y-y1=m(x-x1)
m=4
y-4=4(x-(-1))
y-4=4(x+1)
Answer:
false. the sqrt of -1 = i
Step-by-step explanation:
Answer:
A and E
Step-by-step explanation:
The given problem shows a graph of a vertical line with an undefined slope, in which its equation is x = 3 (which matches Option A).
It is not considered a function because it has the same input for every given output. This means that regardless of its y-coordinate, its corresponding x-coordinate will always be x = 3.
The Vertical Line Test allows us to know whether or not a graph is actually a function. Remember that a function can only take on one output for each input. We cannot plug in a value and produce two output values. Since the graph represents a vertical line, it automatically fails the vertical line test. Therefore, it is not a function.
Because it is not a function, Options B, C, and D are invalid answers.
Hence, the correct answers are Options A and E.
A function is differentiable if you can find the derivative at every point in its domain. In the case of f(x) = |x+2|, the function wouldn't be considered differentiable unless you specified a certain sub-interval such as (5,9) that doesn't include x = -2. Without clarifying the interval, the entire function overall is not differentiable even if there's only one point at issue here (because again we look at the entire domain). Though to be fair, you could easily say "the function f(x) = |x+2| is differentiable everywhere but x = -2" and would be correct. So it just depends on your wording really.
Set it up 180=(7x+10)+ z because angle b is on the flat line and then solve for x (180-10, then 170/7) and you’ll get the value of x and from there you can put it in all
