Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
C- Section, also known as a caesarean section.
The selective pairing of adenine (A) with thymine (T) and guanine (G) with cytosine (C) is based on the number of hydrogen bonds established between one of the purine bases and the one pyrimidine bases
<span>The answer would be A. it would not be D because marine life does not concern metals and other resources like that. It would be A because life needs carbon, it already does, but it needs to be well balanced and not disrupted.
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Answer:
This is the digestive system.
Explanation:
We can tell that this is the digestive system because we can see #1: The stomach, #2: The small intestine, #3: The large intestine, and #4: The liver. Hope this helped!
