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snow_lady [41]
3 years ago
14

A square pyramid has sides of 4 m. Each face is an equilateral triangle. What is the lateral area of the pyramid?

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

The lateral area is equal to

LA=64\sqrt{3}\ m^{2}

Step-by-step explanation:

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Can somebody solve this please?
11111nata11111 [884]

Answer:

220

Step-by-step explanation:

Now, I'm not sure if 220 is correct, but I'll explain my reasoning.

We know three angles of a triangle add up to 180 degrees.

So, the smaller triangle has 70 degrees and <em>a</em><em> </em>and <em>b</em><em> </em>variables. By virtue, <em>a</em><em> </em>+ <em>b</em><em> </em>+ 70 = 180.

So, <em>a</em><em> </em><em>+</em> <em>b</em><em> </em>= 110.

Likewise, when you look at the whole triangle, 70 degrees is also one of the angles while <em>c</em><em> </em>and <em>d</em><em> </em>are unknown.

So, <em>c</em><em> </em>+ <em>d</em> + 70 = 180.

This means <em>c</em><em> </em>+ <em>d</em><em> </em>= 110.

So, <em>(</em><em>a</em><em> </em>+<em> </em><em>b</em><em> </em>) +<em> </em><em>(</em><em>c</em><em> </em>+<em> </em><em>d</em><em> </em><em>)</em><em> </em><em>=</em><em> </em>

110 + 110 =

220 degrees.

I hope this helps!

4 0
2 years ago
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