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2 years ago

Please help fast ill give brainliest

Mathematics

2 answers:

salantis [7]2 years ago

3 0

Answer:

5y + 4 and 7y + 4 - 2y

Step-by-step explanation:

Look at the second choice:-

5y + 4 and 7y + 4 - 2y

Simplifying the second expression:-

7y + 4 - 2y

= 5y + 4

So both expressions are equivalent . Therefore if you plug in 2 or 5 the results will be the same.

Nostrana [21]2 years ago

3 0

Answer:

Second option:

5y+4 and 7y+4-2y

Step-by-step explanation:

1. y=2→2y-1=2(2)-1=4-1→2y-1=3

y=2→3y-5+y→3(2)-5+2=6-5+2→3y-5+y=3

y=5→2y-1=2(5)-1=10-1→2y-1=9

y=5→3y-5+y→3(5)-5+5=15-5+5→3y-5+y=15

2y-1 is not equivalent to 3y-5+y when y=2 and y=5

2. y=2→5y+4=5(2)+4=10+4→5y+4=14

y=2→7y+4-2y→7(2)+4-2(2)=14+4-4→7y+4-2y=14

y=5→5y+4=5(5)+4=25+4→5y+4=29

y=5→7y+4-2y→7(5)+4-2(5)=35+4-10→7y+4-2y=29

5y+4 is equivalent to 7y+4-2y when y=2 and y=5

3. y=2→y+7=2+7→y+7=9

y=2→y+2+y→2+2+2→y+2+y=6

y+7 is not equivalent to y+2+y when y=2 and y=5

4. y=2→3y-4=3(2)-4=6-4→3y-4=2

y=2→3y-2+y→3(2)-2+2=6-2+2→3y-2+y=6

3y-4 is not equivalent to 3y-2+y when y=2 and y=5

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Need help on the answer

lions [1.4K]

Answer:

The second choice is the answer.

Step-by-step explanation:

In math, there are two types of numbers: real numbers and imaginary numbers. Imaginary numbers build upon the premise that the equation

x^2 +1 = 0 has no real solution. It is said that one of the imaginary solutions to this equation is i, or √-1. Real numbers are numbers that can represent the "distance" of a line. Real numbers have subsets known as natural numbers, whole numbers, integers, natural numbers. It also has a region of irrational numbers.

Natural numbers are numbers you use to count w/ your fingers (1, 2, 3 ...)

Whole numbers are natural numbers and 0 (0, 1, 2, 3 ...)

Integers are whole numbers and their opposites ( -1, 0, 1, ...)

Rational numbers integers and numbers that can be put into a fraction of two integers. for example, 1/2 is a fraction of the integers 1 and 2 ( -1, -1/2, 0, 1/2, 1 ...)

Irrational numbers are numbers that cannot be written as a simple fraction or cannot be written as terminating or repeating decimals (√2, π, e, ...).

The answer is not the first choice because it has whole numbers.

The answer is not the third choice because it has integers.

The answer is not the fourth choice because it has irrational numbers.

The answer is not the fifth choice because it has imaginary numbers.

The second choice is the one that has rational numbers and is the answer.

4 0

3 years ago

The sum of Eric’s and Bob’s weights is 9 times the difference of their weights. The positive difference of their weights is also

Pie

Answer:

150

Step-by-step explanation:

So I will shorten Eric, and Bob's names as E, and B.

So the equations are this

B-E = B+E - 240, E as Eric, and B as Bob, and this E+B=9(E-B)

Move the variables and you get

-2E =- 240

Just divide them both by -2

and E=120

So when we know the value of E we can just plug it into the 1st question

120+B=9B+1080

Moves the Variables and numbers to the other side

8B=1200

1200/8= 150

B=150

There is Bob's weight

6 0

2 years ago

Please help I really don’t know what to do

just olya [345]

Answer:

The answer is 0

Step-by-step explanation:

2 * 2 * 2 = 8

8 * 0.5 = 4

4 - 4 = 0

0 / 2 = 0

Make sure the 0.5 is actually 0.5, because it is hard to tell in that expression. if anything, anything, the steps are the same and all you would need to do is the change the numbers.

Hope this helps :)

7 0

3 years ago

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

2 years ago

Slope intercept form that passes though the point (-2,-3) and has a slope of 5/2

olganol [36]

$\text{Given that,}\\\\(x_1,y_1) = (-2,-3), ~~\text{and slope,}~~m = \dfrac 52\\\\\\\text{Now,}\\\\y -y_1 =m(x-x_1)\\\\\implies y +3 = \dfrac52 (x+2)\\\\\implies y = \dfrac 52(x+2) -3\\\\\\\implies y = \dfrac{5}2 x + 5 -3 \\\\\\\implies y = \dfrac 52 x + 2\\\\\\\text{This is the slope-intercept form(y =mx+b)}.$

8 0

2 years ago

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