Answer:
Second option:
5y+4 and 7y+4-2y
Step-by-step explanation:
1. y=2→2y-1=2(2)-1=4-1→2y-1=3
y=2→3y-5+y→3(2)-5+2=6-5+2→3y-5+y=3
y=5→2y-1=2(5)-1=10-1→2y-1=9
y=5→3y-5+y→3(5)-5+5=15-5+5→3y-5+y=15
2y-1 is not equivalent to 3y-5+y when y=2 and y=5
2. y=2→5y+4=5(2)+4=10+4→5y+4=14
y=2→7y+4-2y→7(2)+4-2(2)=14+4-4→7y+4-2y=14
y=5→5y+4=5(5)+4=25+4→5y+4=29
y=5→7y+4-2y→7(5)+4-2(5)=35+4-10→7y+4-2y=29
5y+4 is equivalent to 7y+4-2y when y=2 and y=5
3. y=2→y+7=2+7→y+7=9
y=2→y+2+y→2+2+2→y+2+y=6
y+7 is not equivalent to y+2+y when y=2 and y=5
4. y=2→3y-4=3(2)-4=6-4→3y-4=2
y=2→3y-2+y→3(2)-2+2=6-2+2→3y-2+y=6
3y-4 is not equivalent to 3y-2+y when y=2 and y=5
