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Aloiza [94]
3 years ago
7

Question 6 How many significant figures are there in 31.1100?

Chemistry
2 answers:
andrey2020 [161]3 years ago
7 0

Answer:

6 sig figs

Explanation:

sig figs are numbers that are more than 0, but in this case, after the decimal, the 0's at the end count as sig figs as well

ruslelena [56]3 years ago
7 0

There are 6 significant numbers in 31.1100.

If there is no decimal point in the figures then it will be 4 but since there is a decimal point then it is 6 significant figures.

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How much heat is needed to raise the temperature of 100g of an iron from 25°C to
Black_prince [1.1K]

Answer:

382.5J

Explanation:

<em>Use the formula:</em>

E = mcΔθ or Q = mcΔT

m = 100g

c = 0.45 J/g°C

ΔT or Δθ = 110 - 25 = 85°

<em>Sub in the values:</em>

E = 100 × 0.45 × 85

= 382.5J

5 0
3 years ago
Four nails have a total mass of 4.42 grams how many moles of iron atoms do they contain
deff fn [24]

Answer:4.42 g= 1 mol/55.845 =.079 moles of Fe

Explanation:Given 4.42 grams of Fe. The atomic weight of Fe(iron) found on the periodic table is 55.845. Divide grams by the atomic weight to convert to moles.

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4 years ago
What is another name for the sunlit zone of the ocean?
motikmotik

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4 0
3 years ago
Read 2 more answers
What volume of 0.585 m ca(oh)2 would be needed to neutralize 15.8 l of 1.51 m hcl?
SpyIntel [72]
When the balanced reaction equation is:

2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l)

from the balanced equation, we can get the molar ratio between HCl & Ca(OH)2

2:1

∴ the volume of Ca(OH)2 = 15.8 L HCl * 1.51 m HCl * (1mol Ca(OH)2/ 2mol HCl) *                                           (1L ca(OH)2/0.585 mol Ca(OH)2 

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8 0
3 years ago
Please help
ludmilkaskok [199]

Answer: The molecular formula will be C_3H_9

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

The empirical formula is CH_3

The empirical weight of CH_3 = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{45}{15}=3

The molecular formula will be=3\times CH_3=C_3H_9

Thus molecular formula will be C_3H_9

6 0
3 years ago
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