The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
I'm sorry but could you tell me IE2
I couldn't asks for details
Answer:
there are two significant figures is the number 8400
Explanation:
Answer:
New temperature = 546 K
Explanation:
Given that,
Initial volume, V = 200 L
Initial temperature, T = 273 K
We need to find the new temperature if the volume is doubled.
The relation between temperature and volume is direction. If volume is doubled, it means the temperature gets also doubled.
New temperature of the gas = 2(273) = 546 K
Answer:
Hey there! :)
Explanation:
Answers;
165lbs = 74842.74
12.01cm = 0.1201
………………….……………………………………
(Answers will be explained)
~So first let’s do question ‘A’
A. 165 lbs=?? g
~We have to use the formula.
Grams=Pounds X 453.59237
(Note: 1 lb = 453.59237)
~With that being said, we can see that the pounds in 165. So we have to multiply using the formula.
~165 X 453.59237
⇒ Equals to 74842.74
So question ‘A’ is 74842.74
==================================================
~Okay now let’s do question ‘B’
B. 12.01 = ?? m
~Let’s first see what the formula is.
~Meters = Centimeter * 0.01
Or...
~Meter = Centimeter / 100
(Note: 1 m = 100 cm)
~Okay now let’s use the formula to find the answer.
(We use the formula)
12.01 / 100
⇒ Equals to 0.1201
~Hope this helps!~
^^Good luck!^^
~Have a nice day! :P
~If you have any questions about the steps, than ask for help! I would be glad to help with anything you don’t understand! :)
^-^ Also if you need help with other questions, I might be free to answer them too!
