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den301095 [7]
3 years ago
14

Why does a star grow larger after it exhausts its core hydrogen?

Physics
1 answer:
arlik [135]3 years ago
4 0

Because Helium fusion in a shell outside the core generates enough thermal pressure to push the upper layers outward.

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Brainliest if correct Question 1 of 10
Art [367]

Answer:

B

Explanation:

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2 years ago
The image shows one complete cycle of a mass on a spring in simple harmonic motion. An illustration of a mass on a vertical spri
Alja [10]

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D. "The net force is zero, so the acceleration is zero"

Explanation:

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6 0
3 years ago
child mass 25kg moves with speed of 1.5m/s when 7.8 from the central of merry-go round. calculate the centripetal acceleration o
MAVERICK [17]

Answer:

0.2885 m/s²

Explanation:

The formula for centripetal acceleration is given as;

a_c=v^2/r

Given that;

speed = v = 1.5m/s

radius = r = 7.8

a_c=v^2/r\\\\\\a_c=1.5^2/7.8\\\\\\a_c=0.2885m/s^{2}

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Suppose the electric field between two parallel plates kept constant but the distance between them is tripled. What happens to t
alukav5142 [94]

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3 years ago
Two crates, one with mass 5.4 kg and the other with mass 8.2 kg, connected by a light rope. The coefficient of kinetic friction
Gnom [1K]

Answer:

R= 2.5 :ratio of the magnitude of the applied horizontal force to the magnitude of the tension in the rope connecting the blocks

Explanation:

We apply Newton's second law:

∑F=m*a

velocity  is constant ,then , a=0

Nomenclature

W: weight

m: mass

N : normal force

Ff: Friction force

μk: coefficient of kinetic friction

T: tension  force in the rope

F: applied horizontal force

g: acceleration due to gravity.

Force Calculation

W₁=m₁*g=5.4 kg *9.8m/s²=52.92 N

W₂=m₂*g=8.2 kg *9.8m/s²= 80.36N

∑Fy=0  

N₁-W₁=0 , N₁=W₁ = 52.92 N

N₂-W₂=0, N₂=W₂=80.36N

Ff₁= μk* N₁=0.4*52.92 N = 21.16N

Ff₂= μk* N₂=0.4*80.36N = 32.14N

Look at the attached graphic

Free-Body diagram m₁=5.4 kg

∑Fx=0

T- Ff₁=0 , T= Ff₁     ,    T= 21.16N

Free-Body diagram m₂=8.2 kg

∑Fx=0

F-T- Ff₂=0 , F=T+Ff₂= 21.16N+32.14N=53.3N

Ratio of the magnitude of the applied horizontal force to the magnitude of the tension in the rope connecting the blocks (R)

R= F/T= 53.3N/21.16N = 2.5

3 0
3 years ago
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