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Answer:
The magnitude of magnetic field at given point = × T
Explanation:
Given :
Current passing through both wires = 5.0 A
Separation between both wires = 8.0 cm
We have to find magnetic field at a point which is 5 cm from any of wires.
From biot savert law,
We know the magnetic field due to long parallel wires.
⇒
Where magnetic field due to long wires, , perpendicular distance from wire to given point
From any one wire 5 cm, 3 cm
so we write,
∴
Therefore, the magnitude of magnetic field at given point =
Answer:
The initial velocity was U=22.14m/s
Explanation:
Step one :
Applying the third equation of motion
v² = u²+ 2as
Where v= Final velocity
U =initial velocity
a= acceleration due to gravity
S= distance or displacement
Step two :
V= 0
a= 9.81m/s²
S=25m
U=?
Step three :
Substituting into the equation we have
0²=U²+2*9.81*25
0=U²+490.5
U²=-490.5
U=√490.5
U=22.14m/s
Answer:
the horizontal distance is 4.355 meters
Explanation:
The computation of the horizontal distance while travelling in the air is shown below:
Data provided in the question is as follows
Velocity = u = 7.70 m/s
H = 1.60 m
R = horizontal direction
Based on the above information
As we know that
R = u × time
where,
Time =
So,
=
= 4.355 meters
hence, the horizontal distance is 4.355 meters
Answer:
The distance is 5 m.
Explanation:
Given that,
Horizontal velocity = 20.0 m/s
Time t = 0.250 s
We need to calculate the horizontal distance
The distance traveled by the baseball with horizontal velocity in time t is given by
Using formula for horizontal distance
Hence, The distance is 5 m.