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dem82 [27]
3 years ago
10

A piece of wood is floating in a tub of water. A second piece of wood rests on top of the first piece; it does NOT touch the wat

er. If the second piece of wood is removed from on top of the first piece and placed in the water, what happens to the water level in the tub? a. The water level cannot be determined without additional information. b. The water level drops. c. The water level remains unchanged. d. The water level rises.
Physics
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

C)

Explanation:

The buoyancy and weight of the wood have to be equal for the system to be in equilibrium. The total mass (then, weight) of the wood is the same, so the total buoyancy has to be the same. Since buoyancy is the weight of the liquid displaced, the volume of liquid displaced will be the same in either case, which means that the water level will remain unchanged.

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in the diagram, q2 is +34.4*10^-6 C, and q3 is -72.8*10^-6 C. The net force on q2 is 225 N to the right. What is q1? Include the
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Answer:

  q₁ = -6.54 10⁻⁵ C

Explanation:

Force is a vector quantity, but since all charges are on the x-axis, we can work in one dimension, let's apply Newton's second law

                F = F₁₂ + F₂₃

the electric force is given by Coulomb's law

                F = k q₁q₂ / r₁₂²

let's write the expression for each force

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                F₂₃ = 9 10⁹ 34.4 10⁻⁶ 72.8 10⁻⁶ / 0.1²

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                F₁₂ = 9 10⁹ q₁ 34.4 10⁻⁶ / 0.1²

                F₁₂ = q₁   3,096 10⁷ N

we substitute in the first equation

                225 = q₁  3,096 10⁷ +2.25 10³

                q₁ = (225 - 2.25 10³) / 3,096 10⁷

                q₁ = -6.54 10⁻⁵ C

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