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Lerok [7]
2 years ago
7

What pressure is exerted on the bottom of a 0.500-m-wide by 0.900-m-long water tank that can hold 50.0 kg of water by the weight

of the water in it when it is full
Physics
1 answer:
svetoff [14.1K]2 years ago
3 0

Answer:

1088.9N/m2

Explanation:

Calculation for What pressure is exerted

First step is to find the area of bottom of the tank using formula

Area=Width*breadth

Let plug in the formula

Area=0.5*0.9

Area=0.45m2

Now let calculate what pressure is exerted using this formula

Pressure=Force/Area

Where,

Force=Mass *Gasoline

Area=Width of the tank* Length of the tank

Let plug in the formula

Pressure=50*9.8/0.5*0.9

Pressure=490/0.45

Pressure=1088.9N/m2

Therefore What pressure is exerted is 1088.9N/m2

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Blood is a homogenous mixture

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At what frequency should a 200-turn, flat coil of cross sectional area of 300 cm2 be rotated in a uniform 30-mT magnetic field t
Alexxandr [17]

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turns of the coil, 200 turn

cross sectional area of the coil, A = 300 cm² = 0.03 m²

magnitude of the magnetic field, B = 30 mT = 0.03 T

Maximum value of the induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

Where;

ω is angular frequency = 2πf

E = NBA(2πf)

f = E / 2πNBA

f = (8) / (2π x 200 x 0.03 x 0.03)

f = 7.07 Hz

Therefore, the frequency of the coil is 7.07 Hz

7 0
3 years ago
A simple pendulum having a length of 1.02 m and a mass of 6.66 kg undergoes simple harmonic motion when given an initial speed o
attashe74 [19]

Answer:

<em>Time period of pendulum is 2.02 s.</em>

Explanation:

A <em>simple pendulum</em> is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.

The time period of pendulum is defined as time taken by the pendulum to complete one full oscillation . it is denoted by T.

By <em>Huygens law of period of pendulum</em>,

T = 2π\sqrt{\frac{L}{g} }   eqn 1

where L is the length of pendulum,

          g is acceleration due to gravity

<em>Period of pendulum is independent of the mass of pendulum,</em>

<em />

Substituting values in eqn 1

T = 2π \sqrt{\frac{1.02}{9.8\\} }

T =   2.02 s

<em>Time period of pendulum is 2.02 s.</em>

4 0
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Two hicers are 13 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walk
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Answer:

Explanation:

Let r be the rate of the slower walker in mph

[r + (r + 1.7)](2) = 13

    (2r + 1.7)(2) = 13

         4r + 3.4 = 13

                  4r = 9.6

                    r = 2.4 mph

            r + 1.7 = 4.1 mph        

5 0
3 years ago
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