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Lerok [7]
3 years ago
7

What pressure is exerted on the bottom of a 0.500-m-wide by 0.900-m-long water tank that can hold 50.0 kg of water by the weight

of the water in it when it is full
Physics
1 answer:
svetoff [14.1K]3 years ago
3 0

Answer:

1088.9N/m2

Explanation:

Calculation for What pressure is exerted

First step is to find the area of bottom of the tank using formula

Area=Width*breadth

Let plug in the formula

Area=0.5*0.9

Area=0.45m2

Now let calculate what pressure is exerted using this formula

Pressure=Force/Area

Where,

Force=Mass *Gasoline

Area=Width of the tank* Length of the tank

Let plug in the formula

Pressure=50*9.8/0.5*0.9

Pressure=490/0.45

Pressure=1088.9N/m2

Therefore What pressure is exerted is 1088.9N/m2

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Using the equation: Q = mL
Q = 1(100) Q = 100cal
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An elevator cab is pulled directly upward by a single cable. The elevator cab and its single occupant have a mass of 2300 kg. Wh
Murrr4er [49]

Answer:

15.64 KN

Explanation:

mass of the elevator cab with a single occupant= 2300 kg

acceleration relative to the cab a_{ce}= 6.80 m/s^2

acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2

The acceleration of elevator cab relative to the ground a_{cg}

now we can say that

a_{ce} +a_{eg} =a_{cg}

=-6.80+ a_{eg}= -9.8

[tex]a_{eg}=-9.8+6.80=-3.8

The forces that act on elevator cab are tension and gravitational, applying newtons second law

T- mg= ma_{eg}

Then the tension in the cable is

T= 2300(-3.8)+2300×9.8=  15640 N= 15.64 KN

therefore tension in the string will be 15.64 KN

3 0
3 years ago
Name three ways electricity can be produced.​
Naya [18.7K]

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For atomic hydrogen, the Paschen series of lines occurs when nf = 3, whereas the Brackett series occurs when nf = 4 in the equat
zvonat [6]

Answer:

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

Explanation:

The Rydberg equation is given by

\frac{1}{\lambda} =\frac{2\pi mk^2e^4}{h^3c} t (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

m is the mass of electron

k = 1/4π∈₀

∈₀ = is the permitivity of free space

e is the charge of electron

h is the plank constant

c is the speed of light in vaccum

z is the atomic number = 1

\frac{1}{\lambda} =R (\frac{1}{n^2_f}-\frac{1}{n^2_i}  )

where R is the  Rydberg constant = 1.097373 × 10⁷m⁻¹

For  Paschen series of H spectrum

n_f = 3

n_i = 5,6,7 ...

in Paschen series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{16} )\\\\\lambda_m_a_x=1874.6nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{9} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=820.14nm

The brackett series of H spectrum

The maximum wavelength occur for n_i = 4

\frac{1}{\lambda_m_a_x } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{25} )\\\\\lambda_m_a_x=4050.05nm

The minimum wavelength occur for n_i = ∞

\frac{1}{\lambda_m_i_n } =(1.097373 \times 10^7)(\frac{1}{16} - \frac{1}{_o_o} )\\\\\lambda_m_a_x=1458.03nm

(\lambda_{max} )_{brackett} < (\lambda_{min} )_{paschen}

So the two wavelength range will over lap

8 0
3 years ago
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