D
Because the rest of the answers are illogical
The magnitude of a point charge is 0.189 x 10⁻⁹C.
<h3>Steps</h3>
We have stated that the point charge's electric field is E=2.5 N/C.
Distance from point charge R = 51 cm = 0.51 m
We are aware that the electric field resulting from a point charge is given as E = 1 / 4π∈₀ × Q / R²
so 2.5 = 9 x 10⁹ Q/ 0.68²
The magnitude of a point charge is 0.189 x 10⁻⁹C.
The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.
From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
learn more about electric field here
brainly.com/question/14372859
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Answer:
I'm pretty sure that the answer is A
