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Georgia [21]
3 years ago
8

If a student can run the mile in 8 minutes, how many miles can they run in an hour?

Mathematics
1 answer:
trapecia [35]3 years ago
6 0

The answer is:   "  7 \frac{1}{2}  \frac{mi }{hr} "  ;

_____________________________________________

    or, write as:  " 7. 5  \frac{mi}{hr} " .

_____________________________________________

Explanation:

To solve:

_____________________________________________

Using a technique called "dimensional analysis" :

_____________________________________________

  \frac{1 mi}{8 min} * \frac{60 min}{1 hr}  ;

               =     \frac{(1 * 60)}{(8 * 1 )}   \frac{mi}{hr}

               =     \frac{60}{8}  \frac{mi}{hr} ;

               =     \frac{(60/4)}{(8/4)}  \frac{mi}{hr} ;

               =    \frac{15}{2}   \frac{mi}{hr}  ;

               =    { 15 ÷ 2 }  \frac{mi}{hr}

               =      "  7 \frac{1}{2}  \frac{mi }{hr} " .  

_____________________________________________

or, write as:     "  7. 5  \frac{mi}{hr}  " .

_____________________________________________

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Answer:

t = 64g

Step-by-step explanation:

This is quite straightforward

Let n be the number of tokens he is charged per game.

88 = 2200 - 33n

33n = 2200 - 88

33n = 2112

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Now, we write the relation. The number of tokens t at any point in time is 64 multiplied by the number of games

t = 64g

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3 years ago
A circle with a radius of 5 is inscribed in a equilateral triangle. What is the area of the triangle's area minus the circle's a
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3 years ago
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3 0
3 years ago
Read 2 more answers
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xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 :      2x+y=(-4)

Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

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3 years ago
a function f(x) is described by the ordered pair (x,y). if given the function is translated 2 units to the right and then reflec
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