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puteri [66]
3 years ago
5

A toy company produces two kites whose shapes are geometrically similar. Find the length of the missing side of the smaller kite

Mathematics
1 answer:
docker41 [41]3 years ago
5 0
M=30/22,5=1,33
m=25/x=1,33. ...>x=25/1,33=18,7
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Consider the expression 6n^2 + 2n + 3. What is the coefficient of n?
Inessa [10]

Answer:

2

Step-by-step explanation:

The coefficient is the number in front of the variable.

So, in this case, the coefficient of n^2 is 6 and of n is 2.

4 0
3 years ago
HELPPPPP!!!!!!!!!!!!!!!!!!
Olin [163]

Answer:

Step-by-step explanation:

All the sides are complete, hence we can use the information given to find just 1 triangle

Triangles

From the given information, we have that:

m<B = pi/6 = 30 degres

c = 10

b = 5

This shows that we can use the cosine rule to find the third side b of the triangle. Since all the sides are complete, hence we can use the information given to find just 1 triangle

3 0
1 year ago
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1. Write an expression in simplest form for the area of the figure below:<br> (answer pls)
san4es73 [151]

Answer:

(5x+6)(2x+5)-(2x+4)(x+8) simplified is 8x^2+17x-2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
3 years from now, Ron's age will be 2 times that of Miley. Three years ago, Ron's age was 3 times that of Miley.
andrezito [222]

Answer:

M=9

EXPLANATION:

Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.

Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as

R + 3 = 2*(M + 3)

Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as

R - 3 = 3*(M-3)

We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …

R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3

This can be simplified to

2R = 5M - 3

We can divide both sides of the last equation by 2, and obtain ..

(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.

Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.

Using the first equation, we have

(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6

We now have

(5/2) * M + 3/2 = 2M + 6

The left side of this equation can be rewritten as

(5M + 3) / 2, so we obtain

(5M + 3) / 2 = 2M + 6

Multiplying both sides by 2, we have

5M + 3 = 4M + 12

Subtracting 4M and 3 from both sides, we obtain

M = 9

Miley’s present age is 9.

plss give brainliest

3 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
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