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svetoff [14.1K]
2 years ago
13

P1=(-1,3) and P2=(5,-1) Find the distance from p1 to P2

Mathematics
1 answer:
LenaWriter [7]2 years ago
3 0

Answer:

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

x1 = - 1 ; y1 = 3

x2 = 5 ; y2 = - 1

d = Sqrt[(5 - (-1))² + ((-1) - 3)²]

d = Sqrt[(5 + 1)² + (-1 - 3)²]

d = sqrt[(6)^2 + (-4)^2]

d = sqrt(36 + 16)

d = sqrt(52)

d = 7.21

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Answer:

2(b+1+b)= 18

Step-by-step explanation:

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length: l, breadth: b

Because the length of the sandbox is 1 foot longer, it will be:

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The midpoint of K is M(-3, -1). One endpoint is J(-12, -11). What are the coordinates of endpoint K?
Over [174]

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Step-by-step explanation:

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1 year ago
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