P1=(-1,3) and P2=(5,-1)
Find the distance from p1 to P2
1 answer:
Answer:
7.21
Step-by-step explanation:
Given that:
P1=(-1,3) and P2=(5,-1)
Distance between two points :
d = Sqrt[(x2 - x1)² + (y2 - y1)²]
x1 = - 1 ; y1 = 3
x2 = 5 ; y2 = - 1
d = Sqrt[(5 - (-1))² + ((-1) - 3)²]
d = Sqrt[(5 + 1)² + (-1 - 3)²]
d = sqrt[(6)^2 + (-4)^2]
d = sqrt(36 + 16)
d = sqrt(52)
d = 7.21
You might be interested in
Answer:
154$
Step-by-step explanation:
Answer:
=x³-x
=x(x²-1)
=x(x²-1²)
=x(x+1)(x-1)
hope it helps.
Answer:54
Step-by-step explanation:
9+9=18
18+18=36
36+18=54
Hope this helps:)
35
“Negative times a negative is a positive”
