Answer:
See the solution
Step-by-step explanation:
Answer:
hdhwvejrfgnwruge. love that . ask a question though id love to help!
Step-by-step explanation:
you got this buddy lol
Consider a circle with radius centered at some point on the -axis. This circle has equation
Revolve the region bounded by this circle across the -axis to get a torus. Using the shell method, the volume of the resulting torus is
where .
So the volume is
Substitute
and the integral becomes
Notice that is an odd function, so the integral over is 0. This leaves us with
Write
so the volume is
Answer:
6 : 3 : 1
Step-by-step explanation:
Given
: : ( multiply each part by 12 , the LCM of 2, 3, 12 to clear the fractions )
= 6 : 3 : 1
That might be the diameter of the circle