See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
x=-1
Step-by-step explanation:
just like 8/8 is 1 the same concept only you add a negative
Answer:
Tom was speeding.
Step-by-step explanation:
The driving speed of Tom = 20.3 meters per second.
Speed allowed in the zone = 45 miles per hour zone.
Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.
1 mile = 1609.34 meters
1 hour = 3600 second
Now convert 20.3 into mile per hour.
20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.
Since Tom’s speed is more than the allowed speed so he is speeding.
It is the same distance apart. .1875-.125 is .0625
1/4 is .25-.1875 is .0625
Answer:
Step-by-step explanation:
<em>Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.</em>
<em />
<em>Height of male pilot = 74.2 inches</em>
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<em>We have to find the percentile</em>
<em />
<em>X = 74.2</em>
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<em>Corresponding Z score = 74.2-72.6 = 1.6</em>
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<em>P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%</em>
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<em>i.e. only 5% are below him in height.</em>
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<em>Thus the malepilot is in 5th percentile.</em>