Even population distribution refers to a type of population distribution in which the arrangement is done in such a way that the distance between neighboring individual is maximized and uniform. This type of population distribution is usually found on the farm land, where the space in which the crops are planted have been carefully measured out. Thus an example of even population distribution is corn planted in a field.
T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r
where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,
Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r
Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.
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Answer:.
the ball would go down and speed of it would not strike so that wouldnt be an example of the conversation momentum
Explanation:
The answer I think
Answer:
(a) 1.093 rad/s^2
(b) 4.375 rad/s
(c) 8.744 rad/s
(d) 67.845 rad
Explanation:
initial angular velocity, ωo = 0
time, t = 8s
angular displacement, θ = 35 rad
(a) Let α be the angular acceleration.
Use second equation of motion for rotational motion
![\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Comega%20_%7B0%7Dt%2B%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E%7B2%7D)
By substituting the values
35 = 0 + 0.5 x α x 8 x 8
α = 1.093 rad/s^2
(b) The average angular velocity is defined as the ratio of total angular displacement to the total time taken .
Average angular velocity = 35 / 8 = 4.375 rad/s
(c) Let ω be the instantaneous angular velocity at t = 8 s
Use first equation of motion for rotational motion
ω = ωo + αt
ω = 0 + 1.093 x 8 = 8.744 rad/s
(d) Let in next 5 seconds the angular displacement is θ.
![\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Comega%20_%7B0%7Dt%2B%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E%7B2%7D)
By substituting the values
θ = 8.744 x 5 + 0.5 x 1.093 x 5 x 5
θ = 67.845 rad
Ek = 6KJ.
In physics, the kinetic energy of a body or object is the one that owns due to its movement and is given by the equation
, where m is the mass of the object in kilograms and v is the velocity in m/s.
An object that it has a mass of 30 kilograms and moves with a velocity of 20m/s, its kinetic energy is given by:
![E_{k} = \frac{1}{2} (30kg)(20m/s)^{2}=6000J=6KJ](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2830kg%29%2820m%2Fs%29%5E%7B2%7D%3D6000J%3D6KJ)