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3 years ago

What is the slope of a line with endpoints (-11,5) and (5,-7)

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Slope K = (y2-y1)/(x2-x1)
Point 1 = (-11,5) Point 2 = (5,-7)

Slope K = (-7-5)/(5+11) = (-12)/16 = -3/4

krok68 [10]3 years ago

3 0

Answer:

-6/8

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where (X1,y1) is (-11,5) and (X2,y2) is(5,-7)

Slope=5+7/-11-5

=-12/16

= -6/8

So the slope is -6/8

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A local bicycle shop makes $75 on each

katrin [286]

The inequality that show how many of each bike model must be sold so the

company avoids losing money is 75x + 90y ≥ $1350

Let x represent the number of model A bikes produced and y represent the number of model B bikes produced.

Since A local bicycle shop makes $75 on each Model A bike and $90 on each Model B bike, hence:

Revenue = 75x + 90y

The overhead cost is $1350, hence to make profit:

Revenue ≥ cost

75x + 90y ≥ $1350

The inequality that show how many of each bike model must be sold so the

company avoids losing money is 75x + 90y ≥ $1350

Find out more at: brainly.com/question/25285332

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3 years ago

Factor out the expression 2/3 (4x + 9) detailed explanation of how this is done please

krek1111 [17]

Answer:

$\frac{8x}{3} + 6$

Step-by-step explanation:

I think what you mean is to solve the expression. Lets do it!

$\frac{2}{3} (4x + 9)$

=> $\frac{8x}{3} + 6$

Therefore, $\frac{8x}{3} + 6$ is our answer

8 0

3 years ago

Read 2 more answers

PLEASE HELP MEE I'LL MARK U AS BRAINLIEST!!!!

cluponka [151]

Answer:

Step-by-step explanation:

10 divided by 4 is 2.5

and 2.5 times 14 is 35

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3 years ago

Write an equation parallel to y=-x-4 passing through point (4,-4)

Likurg_2 [28]

I think it would be y= -1x but I’m not 100% sure

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4 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago