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AlladinOne [14]
3 years ago
15

2. You and a friend are spending a weekend at a carnival. You get bored and begin to make electrostatics measurements. It turns

out that you have a charge of +3 Coulombs and your friend a charge of -5 Coulombs. What is the net electric charge?A) +2 Coulombs
B) -2 Coulombs
C) +8 Coulombs
D) -8 Coulombs
Physics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

B) -2 Coulombs

Explanation:

In order to find the net charge, we must add the charge that you have with the charge that your friend has, but taking into account the different sign. In fact, we have:

- Charge possessed by you: Q1 = +3 C

- Charge possessed by your friend: Q2 = -5 C

Therefore, the net charge possessed by both persons will be given by

Q = Q1 + Q2 = +3 C + (-5 C) = +3 C - 5 C = -2 C

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Answer:

<em>The gravitational force between Royce and Earth would be doubled at 16 years.</em>

Explanation:

<em>"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".</em>

Royce Scenario

At the age of 10 Royce's mass = 30kg

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In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

6 0
3 years ago
Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an
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Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

F=k_e\frac{q_1q_2}{r^2}

where,

F = electrostatic force of attraction or repulsion

k_e = Coulomb's constant

q_1 and q_2 are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2       ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}     ...........(2)

Equation equation 1 and 2, we get

\frac{F_{sq}}{F_{sp}}=\frac{1}{4}

F_{sq}=4\times F_{sp}

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

5 0
3 years ago
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A horizontal clothesline is tied between 2 poles, 16 meters apart. When a mass of 3 kilograms is tied to the middle of the cloth
Alla [95]

Answer:

The magnitude of the tension on the ends of the clothesline is 41.85 N.

Explanation:

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Mass = 3 kg

Sags distance = 3 m

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Using formula of angle

\tan\theta=\dfrac{8}{3}

\thta=\tan^{-1}\dfrac{8}{3}

\theta=69.44^{\circ}

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Using formula of tension

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Put the value into the formula

3\times9.8=2T\times\cos69.44

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4 0
4 years ago
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What is 1113.28 in a sig fig?
Afina-wow [57]

Answer:

6 significant figure

Explanation:

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