Answer:
2,4,5 are the answers
Explanation:
sky diver suit, helicopter and feather hAVE an external force pushing or floating them
Answer:
559.5 N
Explanation:
Applying,
v² = u²+2gs............. Equation 1
Where v = final velocity,
From the question,
Given: s = 5.10 m, u = 0 m/s ( from rest)
Constant: 9.8 m/s²
Therefore,
v² = 0²+2×9.8×5.1
v² = 99.96
v = √(99.96)
v = 9.99 m/s
As the diver eneters the water,
u = 9.99 m/s, v = 0 m/s
Given: t = 1.34 s
Apply
a = (v-u)/t
a = 9.99/1.34
a = -7.46 m/s²
F = ma.............. Equation 2
Where F = force, m = mass
Given: m = 75 kg, a = -7.46 m/s²,
F = 75(-7.46)
F = -559.5 N
Hence the average force exerted on the diver is 559.5 N
Answer:
.25 Hz
Explanation:
Period = 4 sec
freq = 1/p = 1/4 hz = .25 Hz
Explanation:
Momentum is directly proportional to velocity. If momentum of an object is doubled , but itsmass does not increase (so velocity remains below the speed of light) then its velocity isdoubled. If the velocity is doubled, then the kinetic energy increases by four times.