Okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t
now, find the half, set a(t)= half the original and solve for t
14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t
t=in(0.5)/(-0.1359)= (aprox) 5.1 days
Answer:
Step-by-step explanation:
A+C = 180 = A + 74 -> A = 106
B +D = 180 = B +88 -> D = 92
x = 92
Answer:
a) f(x) = 3sin(2x - π/2) + 1
b) f(x) = 2sin(2x + π) + 2
Step-by-step explanation:
∵ f(x) = Asin(Bx - C) + D
Where ΙAΙ is the the amplitude , 2π/ΙBΙ is the period , -C/B is the horizontal shift and D is the vertical shift
a) The amplitude is 3
The period is π
Shift phase: horizontally π/4 to the right , vertically 1 unit up
b) The amplitude is 2
The period is π
Shift phase: horizontally π/2 to the left , vertically 2 unit up
Answer:
(- 4, 1 )
Step-by-step explanation:
A translation (x + 1), y - 3 ) means add 1 to the original x- coordinate and subtract 3 from the original y- coordinate.
B = (- 5, 4 ), thus
B' = (- 5 + 1, 4 - 3 ) = (- 4, 1 )
Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].
Suppose f(x) is an odd function. What is the range of 0.5f(x-3) is [-1.5, 0.5]
