A small piece of Cr metal reacts with dilute HNO3 to form H2 (g), which is collected over water at 18 C in a large flask. The to
tal pressure in the flask is 753 mmHg.
Determine the partial pressure of the H2 present.
Determine the partial pressure of the H2 present.
2 answers:
Answer:
The partial pressure of the H₂ is 737.5 mmHg
Explanation:
The partial pressure of the H₂ is equal to:
Where PH₂O is the partial pressure for the water. Clearing the partial pressure of H₂:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The partial pressure is
Explanation:
The Partial pressure of is mathematically represented as
Where is the total pressure of water with a value of 15.5 mm of Hg
is the partial pressure of water with a value 753 mm of Hg
Now substituting values
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Answer:
pH ≅ 4.80
Explanation:
Given that:
the volume of HN₃ = 25 mL = 0.025 L
Molarity of HN₃ = 0.150 M
number of moles of HN₃ = 0.025 × 0.150
number of moles of HN₃ = 0.00375 mol
Molarity of NaOH = 0.150 M
the volume of NaOH = 13.3 mL = 0.0133
number of moles of NaOH = 0.0133× 0.150
number of moles of NaOH = 0.001995 mol
The chemical equation for the reaction of this process can be written as:
1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water
thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol
Total volume used in the reaction = 0.025 + 0.0133 = 0.0383 L
Concentration of =
= 0.0458 M
Concentration of =
= 0.0521 M
GIven that :
Ka =
Thus; it's pKa = 4.72
pH ≅ 4.80