A small piece of Cr metal reacts with dilute HNO3 to form H2 (g), which is collected over water at 18 C in a large flask. The to
tal pressure in the flask is 753 mmHg.
Determine the partial pressure of the H2 present.
Determine the partial pressure of the H2 present.
2 answers:
Answer:
The partial pressure of the H₂ is 737.5 mmHg
Explanation:
The partial pressure of the H₂ is equal to:
Where PH₂O is the partial pressure for the water. Clearing the partial pressure of H₂:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The partial pressure is
Explanation:
The Partial pressure of is mathematically represented as
Where is the total pressure of water with a value of 15.5 mm of Hg
is the partial pressure of water with a value 753 mm of Hg
Now substituting values
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Answer 1) : According to the complete question attached in the answer,
The radial wave function which is denoted by shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.
Also, the radial probability distribution curve denoted as shown in blue color is observed to touch zero, and shows the place of radial node.
Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by <em>'n'</em>.
It is observed that for any atomic orbital, the total number of nodes will be n-1 .
Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.
Hence, there will be only radial nodes, which is
(n−1 = total number of radial nodes in s orbitals)
According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)
This represents the 5s orbital.
Answer 2) The radial nodes are observed in I'm seeing radial nodes at
,
,
and
.
where represents the hydorgen bohr atomic radius = 0.0529177 nm
Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.
since the unit for the heat of fusion is kJ/mol, you're going to have to convert the grams into moles in order to cancel out the unit. After that, you can solve like normal.
