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3 years ago

How did democtitis define atom?

1 answer:

8 0

Democritus, theorized that atoms were specific to the material which they composed. In addition, Democritus believed that the atoms differed in size and shape, were in constant motion in a void, collided with each other; and during these collisions, could rebound or stick together.

<u>Explanation:</u>

One of the main atomic theorists was Democritus, a Greek philosopher who lived in the fifth century BC. Democritus realized that if a stone was partitioned fifty-fifty, the two parts would have indistinguishable properties from the whole.
Therefore, he contemplated that if the stone were to be constantly cut into littler and littler pieces at that point; sooner or later, there would be a piece that would be so little as to be inseparable. He called these small pieces of matter as "atomos", the Greek word for inseparable.

Democritus estimated that atoms were explicit to the material which they made. Also, Democritus accepted that the particles varied in size, were an inconsistent shape, crashed into one another; and during these impacts, could bounce back or stay together. Hence, changes in the matter were a consequence of separations or mixes of the atoms as they moved all through the void.

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Ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with

ankoles [38]

Answer:

$n_{NH_3}=0.18molNH_3$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$H_3PO_4(aq)+3NH_3(l)\rightarrow (NH_4)_3PO_4$

In such a way, considering the 3 to 1 molar relationship between ammonia and ammonium phosphate, the moles of ammonia result:

$n_{NH_3}=0.060mol(NH_4)_3PO_4*\frac{3molNH_3}{1mol(NH_4)_3PO_4}\\n_{NH_3}=0.18molNH_3$

Best regards.

8 0

3 years ago

When N2(g) reacts with H2(g) to form NH3(g), 92.2 kJ of energy are evolved for each mole of N2(g) that reacts. Write a balanced

Naddika [18.5K]

Answer:

N₂ + 3H₂ → 2NH₃ ΔH = - 92.2KJ

Explanation:

Let's write out the chemical equation between Nitrogen and Hydrogen to Form Ammonia.

Nitrogen + Hydrogen = Ammonia

N₂ + H₂ → NH₃

A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH.

The balanced stoichiometric chemical equation is given as;

N₂ + 3H₂ → 2NH₃

92.2 kJ of energy are evolved for each mole of N2(g) that reacts. And from the equation, 1 mole of N2 reacts.

The enthalpy change, ΔH = - 92.2KJ. The negative sign is because heat is being evolved.

The balanced thermochemical equation;

N₂ + 3H₂ → 2NH₃ ΔH = - 92.2KJ

6 0

3 years ago

Which is a cause of physical weathering but not of chemical weathering ??

Soloha48 [4]

Wind becuase you can feel it whhich is physical

8 0

3 years ago

You are given a solid that is a mixture of na2so4 and k2so4.

Murljashka [212]

Here we have to calculate the amount of $SO_{4}^{2-}$ ion present in the sample.

In the sample solution 0.122g of $SO_{4}^{2-}$ ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ + $SO_{4}^{2-}$

(Na)₂SO₄=2Na⁺ + $SO_{4}^{2-}$

Thus, BaCl₂+ $SO_{4}^{2-}$ = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of $SO_{4}^{2-}$ ion is precipitated in this reaction.

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion ( $SO_{4}^{2-}$ ) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present. So in 1 g of BaSO₄ $\frac{96.06}{233.3}=0.411$ g of $SO_{4}^{2-}$ ion is present.