<u>Answer-</u>

<u>Solution-</u>
We know that arc length is the product of radius and central angle in radian.
i.e 
Here,

So,




Answer:
Its A
Step-by-step explanation:
Answer:
a. Alternate exterior angles.
b. <A and <B are congruent. This diagram involves a line intersecting two parallel lines, forming the congruent angles <A and <B on opposite sides of the transversal.
c. They are alternate exterior angles like <A and <B, but because it is not guaranteed that the transversal is intersecting parallel lines in this case, we cannot prove that <C and <D are congruent alternate exterior angles.
A is the answer:)))))))))))))))))))))))
Special cases of the sum and difference formulas for sine and cosine yields what is known as the double‐angle identities and the half‐angle identities.