<u><em>Answer:</em></u>
Radius of the ball is approximately 6.5 cm to the nearest tenth
<u><em>Explanation:</em></u>
The ball has the shape of a sphere
<u>Surface area of a sphere can be calculated using the following rule:</u>
Surface area of sphere = 4πr² square units
<u>In the given problem, we have:</u>
Surface area of the ball = 531 cm²
<u>Substitute with the area in the above equation and solve for the radius as follows:</u>
which is approximately 6.5 cm to the nearest tenth
Hope this helps :)
Answer:
.8
Step-by-step explanation:
Answer:
b=41
Step-by-step explanation:
180=19v-41+(180-(20v+39))+17v
v=5
180=19v-41+b+17v
180=19(5)-41+b+17(5)
b=41
Hello,
Using vectors and scalar product:
![[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0](https://tex.z-dn.net/?f=%5B%28a%2Bc%29%2A%5Cvec%7Bi%7D%2B%28b-0%29%2A%5Cvec%7Bj%7D%20%5D.%5B%28a-c%29%2A%5Cvec%7Bi%7D%2B%28b-0%29%2A%5Cvec%7Bj%7D%5D%3D0%20)
Thus
By the way how can we make text larger in latex \larger{.....} don't work.
Answer A
Step-by-step explanation:
Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.
this is the same as n/2 × (a1 + an), because
an = a1 + (n-1)×d
so, for the series above :
a or a1 = 2
d = 7, as every new term is the previous term plus 7.
for n
37 = a1 + (n-1)×d = 2 + (n-1)×7
and now solve for n
35 = 7n - 7
42 = 7n
n = 6
so, the sum of all terms is
6/2 × (2+37) = 3×39 = 117
