3 years ago

What is the average speed of particles of atoms at room temperature?

Physics

1 answer:

Paha777 [63]3 years ago

8 0

Answer:

300 meters per second. That's equal to about 670 miles per hour.

Explanation:

Not only are air particles incredibly small, they are always moving. And they move fast. At room temperature, they are going about 300 meters per second. That's equal to about 670 miles per hour.

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2. Determine the units of the quantity described by each of the following

notka56 [123]

Explanation:

a.) kg(m/s)(1/s) = force (N)

b.) (kg/s)(m/s) = force (N)

c.) (kg/s)(m/s) = force (N)

d.) (kg/s)(m/s) = force (N)

3 0

2 years ago

What is the volume of a 72 g of copper if copper has a density of 9 g/cm3

azamat

Answer:

8 centimetre cube

Explanation:

because volume is equal to mass per densiry

6 0

3 years ago

A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di

mario62 [17]

Velocity of vw bug is given as

$v_1 = 54 mpH$ towards north

velocity of imphala is given as

$v_2 = 47 mph$ towards south

now we need to find velocity of imphala relative to bug

$v_{21} = v_2 - v_1$

$v_{21} = 47 - (-54) = 101 mpH$

so the speed is 101 mpH towards south so correct option is C

5 0

2 years ago

A car traveling west at 70 miles per hour for 3 hours covers a distance of

gtnhenbr [62]

70x3=210 mph... its that easy

5 0

2 years ago

At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6

Ilia_Sergeevich [38]

Momentum of car

Given: Mass m= 1,400 Kg; V = 6.0 m/s

Formula: P = mv

P = (1,400 Kg)(6.0 m/s)

P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

Mass of rider and bicycle m = 100 Kg

P = mv

V = P/m

V = 8,400 Kg.m/s/100 Kg

V = 84 m/s

7 0

2 years ago