A train moving with a velocity of 42.9 km/hour North, increases its speed with a uniform acceleration of 0.250 m/s^2 North until
1 answer:
Answer:
3658.24m
Explanation:
Hello!
the first thing that we must be clear about is that the train moves with constant acceleration
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf = final speed =160km/h=44.4m/s
Vo = Initial speed =42.9km/h=11.92m/s
A = acceleration =0.25m/s^2
X = displacement
solving
the distance traveled by the train is 3658.24m
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