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nikklg [1K]
3 years ago
11

A wire has a current that flows to the right.

Physics
2 answers:
Reika [66]3 years ago
8 0

answer is DDDDDDDDDDDDDDDDDD


sergejj [24]3 years ago
8 0

D. circles around the wire that go in at the bottom

Explanation:

In order to determine the direction of the magnetic field around the wire, we should use the right's hand rule. First of all, let's keep in mind that the magnetic field around a current carrying wire consists of concentric circles around the wire, so the only possible options are C and D.

In the right-hand rule, we put our thumb in the same direction of the current (so, toward the right). Then we wrap all the other fingers of the hand around the thumb: the direction of the fingers give the direction of the magnetic field. In this case, the fingers go in at the bottom of the thumb (bottom of the wire), so the correct option is

D. circles around the wire that go in at the bottom

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Please help have due very soon?thank you
Andru [333]
The answer is :78 I think
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2 years ago
A 15-turn circular wire loop with a radius of 3.0 cm is initially in a uniform magnetic field with a strength of 0.5 T. The fiel
lana66690 [7]

To solve this problem it is necessary to apply the definition given in Faraday's law in a solenoid for which it is noted that

\epsilon = - d\frac{\phi_B}{dt}

\epsilon = -NA\frac{dB}{dt}

Where,

N = Number of loops

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\epsilon = (15)(\pi(0.03)^2)\frac{0-0.5}{0.1}

\epsilon = 0.212V

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Therefore the correct answer is A.

6 0
3 years ago
47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a
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Answer:

kinetic

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7 0
2 years ago
A 0.01 kg spring toy is compressed 0.02 m and released vertically. The toy is measured to reach 0.25 m in the air. Determine the
Scorpion4ik [409]

Answer:

122.5 N/m

Explanation:

According to the law of conservation of energy, if there is no air resistance or frictional forces, the initial elastic potential energy of the spring toy is entirely converted into gravitational potential energy when the toy reaches the highest point.

Therefore, we can write:

\frac{1}{2}kx^2=mgh

where the term on the left is the initial elastic potential energy while the term on the right is the gravitational potential energy, and where

k is the spring constant

x = 0.02 m is the compression of the spring

m = 0.01 kg is the mass of the toy

h = 0.25 m is the height reached by the toy

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Solving for k,

k=\frac{2mgh}{x^2}=\frac{2(0.01)(9.8)(0.25)}{(0.02)^2}=122.5 N/m

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2 years ago
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Answer:

I remember learning about this in health class. I believe the answer is quality of life.

Explanation:

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