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Gemiola [76]
3 years ago
8

Who want to date me im 13 name is deanna i love dua lipa

Mathematics
1 answer:
german3 years ago
7 0

Answer:

first of all we don't know what u look like

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Rewrite, differentiate and simplify:<br> 3/(2x)^3
Llana [10]

\frac{dy}{dx} = - \frac{9}{8x^{4} }

let y = \frac{3}{(2x)^{3} } = \frac{3}{8} x^{-3}

differentiate using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1}

\frac{dy}{dx} = - \frac{9}{8}x^{-4} = - \frac{9}{8x^{4} }


8 0
3 years ago
It is: THE SUM OF THREE CONSECUTIVE NUMBERS IS 78 WHAT IS THE SMALLEST OF THREE NUMBERS?
TiliK225 [7]
-----------------------------------------------
Define x :
-----------------------------------------------
Let the smallest number be x.
The other two numbers will be x+1 and x+2.

-----------------------------------------------
Construct equation :
-----------------------------------------------
The sum of all 3 numbers is 78
⇒ x + x + 1 + x + 2 = 78

-----------------------------------------------
Solve x :
-----------------------------------------------
x + x + 1 + x + 2 = 78
3x + 3 = 78
3x = 78 - 3
3x = 75
x = 25

-----------------------------------------------
Answer: Smallest number = 25
-----------------------------------------------
8 0
3 years ago
Read 2 more answers
Need help!!! solve for p) n = <br>(p-k)<br> ------<br> j<br><br>Sorry for the terrible fraction
almond37 [142]

Answer:

nj +k = p

Step-by-step explanation:

n = (p-k)/j

Multiply each side by j

nj = (p-k)/j *j

nj = p-k

Add k to each side

nj +k p-k+k

nj +k = p

8 0
3 years ago
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Identify the property that justifies the following statement if 5•m
babymother [125]
Property of multiplication
8 0
3 years ago
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The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
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